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2 years ago

How many grams of carbon dioxide would be formed if 38.9 g C2H2 reacted completely with oxygen

2 answers:

6 0

2C₂H₂ + 5O₂ = 4CO₂ + 2H₂O

m(CO₂)/{4M(CO₂)} = m(C₂H₂)/{2M(C₂H₂)}

m(CO₂)=2M(CO₂)m(C₂H₂)/M(C₂H₂)

m(CO₂)=2*44g/mol*38.9g/26g/mol = 131.7 g

131.7 grams of carbon dioxide would be formed

VLD [36.1K]2 years ago

4 0

The answer is 131.0 g CO2

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When the temperature of the gas changes from cold to hot, the amount of pressure is ___________.

Klio2033 [76]

The pressure would increase. When the temperature change form cold to hot, the gas will find ways to escape from containment. Thus, if it cannot escape that pressure will keep on increasing as the temperature rises.

6 0

2 years ago

Balance the equation :

Sati [7]

The balanced equation is 2 AlI 3 ( a q ) + 3 Cl 2 ( g ) → 2 AlCl 3 ( a q ) + 3 I 2 ( g ) .

Explanation:

Aluminum has a typical oxidation condition of 3+ , and that of iodine is 1- . Along these lines, three iodides can bond with one aluminum. You get AlI3. For comparable reasons, aluminum chloride is AlCl3.

Chlorine and iodine both exist normally as diatomic components, so they are Cl2( g ) also, I2( g ), individually. In spite of the fact that I would anticipate that iodine should be a strong.

Balancing the equation, we get:

2AlI 3( aq ) + 3Cl2 ( g ) → 2AlCl3 ( aq ) + 3 I 2 ( g )

Realizing that there were two chlorines on the left, I simply found the basic numerous of 2 and 3 to be 6, and multiplied the AlCl 3 on the right.

Normally, presently we have two Al on the right, so I multiplied the AlI 3 on the left. Hence, I have 6 I on the left, and I needed to significantly increase I 2 on the right.

We should note, however, that aluminum iodide is viciously receptive in water except if it's a hexahydrate. In this way, it's most likely the anhydrous adaptation broke down in water, and the measure of warmth created may clarify why iodine is a vaporous item, and not a strong.

3 0

3 years ago

With the Haber process, how many grams of hydrogen will be needed to make 0.3820 pounds of ammonia? Needed to 3 decimal places f

masya89 [10]

30.576 g of hydrogen

Explanation:

First we need to covert the pound in grams.

if 1 pound is equal to 453.592 grams

then 0.3820 pounds is equal to X grams

X = (0.3820 × 453.592) / 1 = 173.272 grams

So we have 173.272 grams of ammonia.

Now we look at the chemical reaction where hydrogen (H₂) reacts with nitrogen (N₂) to produce ammonia (NH₃):

3 H₂ + N₂ → 2 NH₃

number of moles = mass / molar weight

number of moles of ammonia = 173.272 / 17 = 10.192 moles

Now taking in account the chemical reaction, we formulate the following reasoning:

if 3 moles of hydrogen produce 2 moles of ammonia

then Y moles of hydrogen produce 10.192 moles of ammonia

Y = (3 × 10.192) / 2 = 15.288 moles of hydrogen

mass = number of moles × molar weight

mass of hydrogen = 15.288 × 2 = 30.576 g

Learn more about:

problems with number of moles

brainly.com/question/13950919

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#learnwithBrainly

4 0

3 years ago

The osmotic pressure of a solution formed by dissolving 75.0 mg of aspirin (c9h8o4) in 0.250 l of water at 25 °c is ________ atm

Igoryamba

Answer is: the osmotic pressure of aqueous solution of aspirin is 0.0407 atm.

m(C₉H₈O₄) = 75 mg ÷ 1000 mg/g = 0.075 g.

n(C₉H₈O₄) = 0.075 g ÷ 180.16 g/mol.

n(C₉H₈O₄) = 0.000416 mol.

c(C₉H₈O₄) = 0.000416 mol ÷ 0.250 L.

c(C₉H₈O₄) = 0.00167 M; concentration of solution.

T(C₉H₈O₄) = 25°C = 298.15 K; temperature in Kelvins.

R = 0.08206 L•atm/mol•K; universal gas constant.

π = c(C₉H₈O₄) • T(C₉H₈O₄) • R.

π = 0.00167 mol/L • 298.15 K • 0.08206 L•atm/mol•K.

π = 0.0407 atm.

3 0

3 years ago

Which is not a compound? A.They are substances B. They have compositions that vary C. They can be physically separated into thei

horsena [70]

Answer:

D.They have properties similar to those of their component elements. 

Explanation:

When elements are joined, the atoms lose their individual properties and have different properties from the elements they are made of .

8 0

3 years ago