Answer:
Yes
Explanation:
Calcium Chloride is an inorganic compound, a salt that can dissolve in water.
The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL
<h3>Balanced equation </h3>
2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O
From the balanced equation above,
- The mole ratio of the acid, H₃PO₄ (nA) = 2
- The mole ratio of the base, Ca(OH)₂ (nB) = 3
<h3>How to determine the volume of Ca(OH)₂ </h3>
- Molarity of acid, H₃PO₄ (Ma) = 0.390 M
- Volume of acid, H₃PO₄ (Va) = 24.5 mL
- Molarity of base, Ca(OH)₂ (Mb) = 0.279 M
- Volume of base, Ca(OH)₂ (Vb) =?
MaVa / MbVb = nA / nB
(0.39 × 24.5) / (0.279 × Vb) = 2/3
9.555 / (0.279 × Vb) = 2/3
Cross multiply
2 × 0.279 × Vb = 9.555 × 3
0.558 × Vb = 28.665
Divide both side by 0.558
Vb = 28.665 / 0.558
Vb = 51.4 mL
Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL
Learn more about titration:
brainly.com/question/14356286
the answer is C) . I hope this was helpful!
The answer would be:
D = M/V
D=Density
M= mass
V= volume
Answer:
Molar concentration of CO₂ in equilibrium is 0.17996M
Explanation:
Based on the reaction:
NiO(s) + CO(g) ⇆ Ni(s) + CO₂(g)
kc is defined as:
kc = [CO₂] / [CO] = 4.0x10³ <em>(1)</em>
As initial concentration of CO is 0.18M, the concentrations in equilibrium are:
[CO] = 0.18000M - x
[CO₂] = x
Replacing in (1):
4.0x10³ = x / (0.18000-x)
720 - 4000x = x
720 = 4001x
x = 0.17996
Thus, concentrations in equilibrium are:
[CO] = 0.18000M - 0.17996 = 4.0x10⁻⁵
[CO₂] = x = <em>0.17996M</em>
<em></em>
Thus, <em>molar concentration of CO₂ in equilibrium is 0.17996M</em>
<em />
I hope it helps!
