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sashaice [31]
3 years ago
12

A coin collection contains nickels and quarters. There are 30 coins in the collection. The number of

Mathematics
2 answers:
photoshop1234 [79]3 years ago
7 0

Answer:

A.17

Step-by-step explanation:

30/2=15

15+2=17

Dafna1 [17]3 years ago
5 0

Answer:

The number of nickels is 8+2q (q being quarters).  so if 8+2q=42, subtract 8 from both sides.  That gives you 2q=34.  Now, divide both sides by 2.  q=17.  17 quarters .

Step-by-step explanation:

Hope This Helps!

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A student earned $175 last week. She worked 35 hours. How much did she earn per hour?
OLEGan [10]

Answer:

should be 5

Step-by-step explanation:

6 0
2 years ago
Points A, B, and C are collinear. Point B is between A and C. Find the length indicated. AB= 5x-15, BC=3x-5, and AC=28. Find AB
katrin2010 [14]

Answer: AB is 15

Step-by-step explanation: First, you need to draw a picture and label the parts of the line: AB=5x-15; BC= 3x-5; AC =28. Because of the segment addition postulate, you set the equation to be 5x-15+3x-5=28. Then you solve:

5x-15+3x-5=28

Add like terms:

8x-20=28

Add 20 to both sides

8x=48

Divide by 8

x=6

Now, you need to find the measure of AB, so you plug the 6 into the x variable for 5x-15

5(6)-15

30-15

AB=15

4 0
2 years ago
At a production process, the produced items are tested for defects. A defective unit is classified as such with probability 0.9,
Snezhnost [94]

Answer:

We use Baye's theorem:  P(A)P(B|A) = P(B)P(A|B)

with (A) being defective and

(B) marked as defective

we have to find P(B) = P(A).P(B|A) + P(¬A)P(B|¬A). .......eq(2)

Since  P(A) = 0.1 and P(B|A)=0.9,

P(¬A) = 1 - P(A) = 1 - 0.1 = 0.9

and

P(B|A¬) = 1 - P(¬B|¬A) = 1 - 0.85 = 0.15

put these values in eq(2)

P(B) = (0.1 × 0.9) + (0.9 × 0.15)

       = 0.225 put this in eq(1) and solve for P(B)

P(B) = 0.4

6 0
2 years ago
PLEASE HELP ME!!!!!!!! 
Delicious77 [7]
Angle θ between two vectors is given by, \theta =cos^{-1}( \frac{u
 \cdot v}{|u||v|} ); where u \cdot 
v=-5(-4)+(-4)(-3)=20+12=32; |u|= \sqrt{ (-5)^{2} + (-4)^{2} } = 
\sqrt{25+16} = \sqrt{41} and |v|=\sqrt{ (-4)^{2} + (-3)^{2} } = 
\sqrt{16+9} = \sqrt{25}=5.
Therefore, \theta =cos^{-1}( \frac{32}{ 5\sqrt{41}} )=cos^{-1}0.9995=1.8^o
3 0
3 years ago
A bookstore sells cookbooks, novels and reference books. The ratio of the number of
Elena-2011 [213]

Step-by-step explanation:

<h3> cookbooks : novels </h3><h3> 2 : 11 </h3><h3> So 6 : 33 </h3>

<h3> cookbooks : reference books </h3><h3> 3 : 4 </h3><h3> So 6 : 8 </h3>

novels : cookbooks : reference books

<h3> 33 : 6 : 8 </h3>
7 0
1 year ago
Read 2 more answers
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