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Lelechka [254]
3 years ago
14

Choose the correct x-intercepts for the following quadratic function.

Mathematics
1 answer:
natali 33 [55]3 years ago
8 0
Brainly doesn't automatically "know" every part of the problems you post here; you have to ensure that your post includes everything in the original problem.

We can still have some fun with answer choice  <span>x = 1, x = 3:

An associated quadratic function would have the form y = a(x-1)(x-3).  Just supposing that the point (2, 5) were on the graph, then this   </span>y = a(x-1)(x-3) would become   5 = a(2-1)(2-3), or 5 = a(1)(-1), or 5 = -a, or a = -5.

Thus, the equation of the parabola would be y = -5(x-1)(x-3), or, in the more usual form, y = -5(x^2 - 4x + 3).

Complete the square to find the vertex:

Steal y = x^2 - 4x + 3 for a moment and complete the square:

x^2 - 4x + 3    =  x^2 - 4x + 4 - 4 + 3, or (x-2)^2  -  1

Subbing this back into    y = -5(x^2 - 4x + 3), we get

y = -5 [ (x-2)^2  -1 ], or   y = -5(x-2)^2 + 5.  This shows that the vertex is at (2, 5), that the graph opens downward, and the graph is symm. about the line x = 2.  

Having fun yet?



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hi

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here  X = 5  so  the multiplicator is  :  1 + 5/100 = 1.05  

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4 0
1 year ago
How do i solve this pls​
miskamm [114]
First we would solve both x’s
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But 3 has the thingy thing (forgot the name haha)
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9x- 5x = 4x
Which leaves 7 and 4x

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melisa1 [442]

Answer:

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4 0
3 years ago
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