<span>The
third root of the given complex number 27(cos(pi/5)+isin(pi/5)) is <span>3(cos(pi/15)+i sin(pi/15))
</span>The solution would be like this
for this specific problem:</span>
<span>2^5 =
32 so you need a 2 out front the 5th root of cos(x) + i sin(x) is
cos(x/5) + i sin(x/5). Additionally, 5 roots are located at even
intervals around the circle. They are spaced every 2 pi/5 or 6 pi/15 radians.
</span>
<span>Roots
are located at pi/15, pi/15+ 10pi/15 = 11 pi/15 and pi/15+ 20pi/15 = 21 pi/15
(or 7 pi /5 ).</span>
Answer:
Solve for
x
by simplifying both sides of the equation, then isolating the variable.
x
=
−
5
Step-by-step explanation:
Answer:
Step-by-step explanation:
PQ*PQ=PQ²=(5x+16)²=25x²+160x+256
If n is the hypotenuse, then it is 37. L can't be the hypotenuse and if m is the hypotenuse then n is 32.878
