All categories

2 years ago

What is the image point of (-3,4)after the transformation D2∘R90∘

1 answer:

7 0

A composite transformation consists of two or more transformations with a procedure of starting from the rightmost transformation

The location of the image of the point (-3, 4), after the transformation $D_2 \circ R90^{\circ}$ is <u>(-8, -6)</u>

Reason:

The given coordinate is (-3, 4)

The required transformation is $D_2 \circ R90^{\circ}$

Solution:

A rotation transformation of (x, y) 90° gives (-y, x)

Therefore;

The rotation of the point (-3, 4) 90° counterclockwise gives (-4, -3)

A transformation of D2 is a dilation by a scale factor of 2

Therefore; D2(-4, -3) gives 2×(-4, -3) = (-8, -6)

Which gives;

The image of (-3, 4), after the transformation $D_2 \circ R90^{\circ}$ → (-8, -6)

Learn more about composite transformations here;

brainly.com/question/12366556

You might be interested in

The members of the Student Activity Council on your campus are meeting to select three speakers for a month-long event celebrat

Komok [63]

The number of different ways that three speakers can be selected is 10 ways

Given the names of choice to be Ben, Will, Stewart, Hilary, and Kate. This means that we have a total of 5 name choices.

If the members of students activities are to select three speakers among these people, the number of ways this can be done is by using the combination rule as shown;

$nCr=\frac{n!}{(n-r)!r!}$

From the question, n = 5 and r = 3. On substituting

$5C3=\frac{5!}{(5-3)!3!}\\5C3=\frac{5!}{2!3!}\\5C3=\frac{5 \times 4 \times 3!}{2 \times 3!} \\5C3=\frac{20}{2}\\5C3 = 10 ways$

Hence the number of different ways that three speakers can be selected is 10 ways.

Learn more here: brainly.com/question/24145745

7 0

2 years ago

90 POINTS!!!!! Given: KLIJ inscr. in k(O),m∠K = 64°, measure of arc LI = 69°, measure of arc IJ = 59°, measure of arc KJ =97°

Kay [80]

In any cyclic quadrilateral, angles opposite one another are supplementary, meaning

$m\angle K+m\angle I=m\angle L+m\angle J=180^\circ$

and given that $\boxed{m\angle K=64^\circ}$ , we have $\boxed{m\angle I=116^\circ}$ .

By the inscribed angle theorem,

$m\angle JLK=\dfrac12m\widehat{KJ}$

$m\angle ILJ=\dfrac12m\widehat{IJ}$

and since

$m\angle L=m\angle JLK+m\angle ILJ$

we have

$m\angle L=\dfrac{97^\circ+59^\circ}2\implies\boxed{m\angle L=78^\circ}$

and it follows that

$m\angle J=180^\circ-m\angle L\implies\boxed{m\angle J=102^\circ}$

5 0

2 years ago

3³ - (4)(2) find da value or die mwaha

eduard

your answer will be 19

6 0

2 years ago

Tim and Cynthia leave Cynthia's house at the same time. Tim drives north and Cynthia drives west. Tim's average speed is 10 mph

RSB [31]

Answer:

54.2 mph

Step-by-step explanation:

Since the drivers leave at the same time and travel in directions 90° from each other, their separation speed can be found using the Pythagorean theorem. Let c represent Cynthia's average speed. Then (c-10) will represent Tim's average speed. Their combined separation speed is 70 miles per hour, so we can write ...

70² = c² +(c -10)²

4900 = 2c² -20c +100 . . . . eliminate parentheses

c² -10c -2400 = 0 . . . . . . . . divide by 2; put in standard form

(c -5)² -2425 = 0 . . . . . . . . . rearrange to vertex form

c = 5 ±5√97 . . . . . . . . . . . . solve for c, simplify radical

c ≈ 54.244 ≈ 54.2 . . . . . . . use the positive solution

Cynthia's average speed was 54.2 miles per hour.

6 0

2 years ago

Graph the point (4, -1) on the coordinate plane below.<br>

dimulka [17.4K]

See the blue dot in the attached image.

First, find the x value on the coordinate plane. The x value is the first number in the point coordinates, so in this case, it is 4. Move to the right 4. (If it was negative, you would move to the left.)

Then, find the y value, which is the second number of the coordinates. In this case, it is -1, so move down 1. (If it was positive, you’d move up.)

Now, mark this point. This is (4, -1).

4 0

3 years ago

Read 2 more answers

What is the image point of (-3,4)after the transformation D2∘R90∘ ​

What is the image point of (-3,4)after the transformation D2∘R90∘