The relevant rules of exponents are
.. (t^a)^b = t^(a·b)
.. t^a·t^b = t^(a+b)
You have
.. (t^-4)^-9·t^2
.. = t^((-4)*(-9) +2)
.. = t^38 . . . . . . . . . . . selection C
The average decrease in value can be solve by first solving the value at year 1 and year 2
and i think the equation is <span>f(x)=10,000(0.73)^x</span>
at x = 1
<span>f(x) = 10,000(0.73)^x
</span><span>f(1) = 10,000(0.73)^(1)
f(1) = 7300
at x = 2
</span><span>f(x) = 10,000(0.73)^x
</span><span>f(2) = 10,000(0.73)^(2)
f(2) = 5329
so the average decrease = ( 7300 - 5329) = $ 1971 per year</span><span>
</span>
-8 3/8 - 2 1/2 = 67/8 - 5/2 = 67/8 - 20/8 = 47/8 also = to 5 7/8
67 - 20 =47
answer: 5 7/8
Answer:
A
Step-by-step explanation:
companies can squeeze workers more than normal
