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a_sh-v [17]
3 years ago
8

Find an equation in slope-intercept form of the line that has slope –7 and passes through point A(8,-4)

Mathematics
2 answers:
Verdich [7]3 years ago
6 0
The answer is D. y= -7x + 52.
BARSIC [14]3 years ago
3 0

Answer:

D

Step-by-step explanation:

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3/4(x+5 1/2) = 5/8<br><br> Distributive Property <br><br> Brainly
Talja [164]

Answer:

x = - \frac{14}{3}

Step-by-step explanation:

Given

\frac{3}{4} (x + 5 \frac{1}{2} ) = \frac{5}{8}

Multiply both sides by 8 to clear the fractions

6(x + 5 \frac{1}{2} ) = 5 ← distribute parenthesis on left side

6x + 33 = 5 ( subtract 33 from both sides )

6x = - 28 ( divide both sides by 6 )

x = \frac{-28}{6} = - \frac{14}{3}

3 0
3 years ago
A computer store bought a program at a cost of ​$20 and sold it at a selling price of ​$25. Find the percent markup.
lions [1.4K]

i dont know, sorry...............................................

5 0
3 years ago
Read 2 more answers
A right square pyramid with base edges of length $8\sqrt{2}$ units each and slant edges of length 10 units each is cut by a plan
seropon [69]

Answer:

32 unit^{3}

Step-by-step explanation:

Given:

  • The slant length 10 units
  • A right square pyramid with base edges of length 8\sqrt{2}

Now we use  Pythagoras to get the slant height in the middle of each triangle:

\sqrt{10^{2 - (4\sqrt{2} ^{2} }) } = \sqrt{100 - 32} = \sqrt{68}  units

One again, you can use Pythagoras again to get the perpendicular height of the entire pyramid.

\sqrt{68-(4\sqrt{2} ^{2} )} = \sqrt{68 - 32} = 6 units.

Because slant edges of length 10 units each is cut by a plane that is parallel to its base and 3 units above its base. So we have the other dementions of the small right square pyramid:

  • The height 3 units
  • A right square pyramid with base edges of length 4\sqrt{2}

So the volume of it is:

V  = 1/3 *3* 4\sqrt{2}

= 32 unit^{3}

5 0
4 years ago
What is the slope of a perpendicular line 2x + y = 6<br><br> is answer -2
Firdavs [7]

Answer:

The slope that is perpendicular to the line will be:

m_2=+\frac{1}{2}

Step-by-step explanation:

Given the equation

2x\:+\:y\:=\:6\:

We know that

y=mx+b is the slope-intercept form of a line where m is the slope and b is the y-intercept.

So, writing the equation in the slope-intercept form

2x\:+\:y\:=\:6\:

\:y=-2x+6

here

m=-2        ∵  y=mx+b        

As we know that for perpendicular lines, one slope is the negative reciprocal of the other.

Therefore, the slope that is perpendicular to the line will be:

m_2=+\frac{1}{2}

3 0
3 years ago
En una P.A. el t(18) es 125 y el t(36) es 251. hallar el término que ocupa el lugar 45.
Ghella [55]

Answer:

161 correo o no ............

8 0
3 years ago
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