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notsponge [240]

3 years ago

8

write the following using algebraic notation using x for unknown numbers i think of a number, add one then double the result

1 answer:

Contact [7]3 years ago

7 0

$y=2(x+1)$ , or $y=2x+2$

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A pilot flew a small plane against the wind 1 miles from Ashland to Roseberg in hour. The pilot returns with the wind miles to A

Maru [420]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Punctele A,B si C sunt coliniare in aceasta ordine.Aflati lungimea segmentului:a)AB,daca AC=20cm,BC=0,12dm

Strike441 [17]

Answer:

The length of the segment AB is 18.8 cm or 1.88 dm

Step-by-step explanation:

<u><em>The question in English is</em></u>

Points A, B and C are collinear in this order. Find the length of the segment: a) AB, if AC = 20 cm, BC = 0.12 dm

we have that

$AC=AB+BC$ ----> by Addition segment postulate

substitute the given values in centimeters

Remember that

$1\ dm=10\ cm$

so

$0.12\ dm=0.12(10)=1.2\ cm$

$20=AB+1.2$

solve for AB

$AB=20-1.2\\AB=18.8\ cm$

Convert to dm

$18.8\ cm=18.8/10=1.88\ dm$

therefore

The length of the segment AB is 18.8 cm or 1.88 dm

3 0

3 years ago

You run one lap around a mile track every eight minutes you're friend runs around the same track every 10 minutes. You both star

labwork [276]

10 , 20 , 30 , 40 , 50
8, 16 , 24, 32, 40

40 minutes

4 0

3 years ago

If P is the incenter of JKL, find each measure

d1i1m1o1n [39]

Answer:

Its really simple look it up at some site

6 0

2 years ago

f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2

iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4, $\infty$ )

g(x)= $2x^2+8x+6=2(x^2+4x+3)$

$g(x)=0$

$2(x^2+4x+3)=0$

$x^2+4x+3=0$

$x^2+3x+x+3=0$

$x(x+3)+1(x+3)=0$

$(x+1)(x+3)=0$

$x+1=0\implies x=-1$

$x+3=0\implies x=-3$

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

$g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2$

$g(x)=2(x^2+4x)+6$

$g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6$

$g(x)=2(x+2)^2-2$

By comparing with the equation of parabola

$y=a(x-h)^2+k$

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2, $\infty$ )

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0

3 years ago