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Pepsi [2]
3 years ago
14

How do you find the slope in a graph?

Mathematics
1 answer:
lys-0071 [83]3 years ago
3 0
Here’s a picture if the formula. M is slope. X1 and Y1 are one coordinate and X2 and Y2 are the other.

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Solve for x plz help fast
erastovalidia [21]

Pythagoras theorem I guess

7 0
3 years ago
Round 43,276 to the nearest 100
bezimeni [28]

Answer:

43,300

Step-by-step explanation:

Starting with 2 since its in the hundredths and going over one place to the tenths, we see 7 <em>is </em> greater than 5 so we make the 2 a 3 and replace everything after with 0's

43,300!!

4 0
3 years ago
1.3( x + 2 )-( y - 6) <br> Help please
mestny [16]
Basically, we need to plug in the given values for the variables x and y into the given expression 1.3(x+2)-(y-6). First off, we can plug in all the given values into the expression, giving us 1.3(4+2)-(2-6). Now, perform the operations on the inside of the parentheses. Doing this, we get 1.3(6)-(-4). Now, we use the distributive property to simplify. This gives us 7.8+4. Finally, when we add the two numbers, we get \boxed{11.8}. Hope this helped!
6 0
3 years ago
Which two properties characterize an air mass?
Lapatulllka [165]

Answer:

Step-by-step explanation: Air masses are given a two-part name that describes the humidity and temperature characteristics of the region where they form

5 0
3 years ago
Read 2 more answers
Use the null hypothesis H0 : μ = 98.6, alternative hypothesis Ha: μ &lt; 98.6, and level of significance α = 0.05. 98 99.6 97.8
andrezito [222]

Answer:

The t-score is -1.8432    

Step-by-step explanation:

We are given the following in the question:  

98, 99.6, 97.8, 97.6, 98.7, 98.4, 98.9, 97.1, 99.2, 97.4, 99.1, 96.9, 98.8, 99.9, 96.8, 97, 98.7, 97.6, 98.7, 98.2

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1964.4}{20} = 98.22

Sum of squares of differences = 16.152

s = \sqrt{\dfrac{16.152}{49}} = 0.922

Population mean, μ = 98.6

Sample mean, \bar{x} = 98.22

Sample size, n = 20

Sample standard deviation, s = 0.922

First, we design the null and the alternate hypothesis

H_{0}: \mu = 98.6\\H_A: \mu < 98.6

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{98.22 - 98.6}{\frac{0.922}{\sqrt{20}} } = -1.8432

The t-score is -1.8432    

7 0
3 years ago
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