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Karo-lina-s [1.5K]
3 years ago
8

Evaluate the expression for x=5, y=-3 and z=7 * 7 – 3y – 3z

Mathematics
1 answer:
kobusy [5.1K]3 years ago
7 0

Answer:

-5

Step-by-step explanation:

i tried my best but this is the result

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You decide to go to the candy store in the mall. You arrive at the store with $25 and then purchase 3 candy bars. You then buy a
Yuri [45]

Answer:

<h2> The cost of a candy is $1.25</h2>

Step-by-step explanation:

given the total amount at hand is $25

let the price of  candy be x

then the cost of 3 candy will  be 3x

the cost of a candy snake is $12.50.

balance at hand after the end of buying $8.75

the total expenses summed up must equal the initial amount at hand which is $25

the expression for the scenario is 3x+12.5+8.75=25

3x+21.25=25

3x=25-21.25

3x=3.75

x=3.75/3

x=$1.25

The cost of a candy is $1.25

4 0
3 years ago
The interior angles formed by the sides of a quadrilateral have measures that sum to 360°.
vova2212 [387]

add all the angles and make them equal to 360

88 + 108 + (3x-6) + 2x = 360

196 + 5x -6 = 360

190 + 5x = 360

5x = 170

x = 34 = answer

4 0
2 years ago
Find the slope of the line that is parallel and perpendicular <br><br> -7x-2y=4
Rus_ich [418]

\bf -7x-2y=4\implies -2y=7x+4\implies y=\cfrac{7x+4}{-2}\implies y=\cfrac{7x}{-2}+\cfrac{4}{-2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{2}} x-2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{7}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{7}}\qquad \stackrel{negative~reciprocal}{\cfrac{2}{7}}}

now, what's the slope of a line parallel to that one above?  well, parallel lines have exactly the same slope.

5 0
3 years ago
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you can only choose 4 unique ways Step-by-step explanation:

6 0
3 years ago
What is the area of a right triangle with a<br>height of 8.9 cm and a base of 14.3 cm?​
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Step-by-step explanation:

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