Please help me Simplify 3✔️2 - ✔️2

Mathematics

1 answer:

MAXImum [283]3 years ago

3 0

$\bf \stackrel{like~terms}{3\sqrt{2}-\sqrt{2}}\implies 2\sqrt{2}$

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3 years ago

Point b is the midpoint of ac-. if ab= 4x+2 and ac=10x-6, find the length of ac

Natasha2012 [34]

let's bear in mind that B is the midpoint and thus it cuts a segment into two equal halves.

$\bf \underset{\leftarrow \qquad \textit{\large 10x-6}\qquad \to }{\boxed{A}\stackrel{4x+2}{\rule[0.35em]{10em}{0.25pt}} B\stackrel{\underline{4x+2}}{\rule[0.35em]{10em}{0.25pt}\boxed{C}}} \\\\\\ AC=AB+BC\implies 10x-6=(4x+2)+(4x+2)\implies 10x-6=8x+4 \\\\\\ 2x-6=4\implies 2x=10\implies x=\cfrac{10}{2}\implies x= 5 \\\\[-0.35em] ~\dotfill\\\\ AC=(4x+2)+(4x+2)\implies AC=[4(5)+2]+[4(5)+2] \\\\\\ AC=22+22\implies AC=44$

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3 years ago

Pls pls help<br> Show work :)

Natasha2012 [34]

9514 1404 393

Answer:

31.243 units

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. Using the attached figure, it is convenient to find the length of BE as an intermediate step in the solution.

Sin = Opposite/Hypotenuse

sin(30°) = BE/100

BE = 100·sin(30°)

Then ...

Tan = Opposite/Adjacent

tan(58°) = BE/x

x = BE/tan(58°) = 100·sin(30°)/tan(58°)

x ≈ 31.243 . . . . units

_____

<em>Comment on the figure</em>

The intermediate problem in creating the figure was to locate point D. That was accomplished by locating point C on a line at an angle of 58° CCW from the horizontal, using point B as a center. Then D is the intersection of BC with the x-axis. BE is drawn perpendicular to the x-axis.

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3 years ago

Please answer please answer

inessss [21]

I attached a photo of my work below; I just screenshotted the photo you provided. I apologize in advance for any mistakes, it’s 1 am and I’m in need of some sleep. However, I hope it helps otherwise. Have a good one!