Answer:
2
Step-by-step explanation:
a1 = -128/27
a2 = 32/9
a3 = -8/3
Therefore, a = a1 = -128/27
r = a3 ÷ a2 = -8/3 ÷ 32/9 = -3/4
So
Therefore, a4 = (-128/27) x (-3/4)^(4-1)
= (-128/27) x (-3/4)^3
= (-128/27) x (-27/64)
= 2
What is the discontinuity and zero of the function
1 answer:
The discontinuity are the point wherein the function is not defined.
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set
then the discontinuity point is at 
.
Comptine the zeroes:
Set
Compute the discriminant:
Then with quadratic formula we get the solutions:
The two zeros are
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set
Comptine the zeroes:
Set
Compute the discriminant:
Then with quadratic formula we get the solutions:
The two zeros are
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