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Agata [3.3K]
3 years ago
8

Check out this right triangular prism: Find the surface area of the right triangular prism (above) using its net (below). units2

^22squared
Mathematics
1 answer:
RoseWind [281]3 years ago
7 0

Answer:

96 squared units

Step-by-step explanation:

Please find attached the diagram used in answering this question

The surface area is equal to the area of each shape

Area of a triangle = Area of a triangle = 1/2 x ( base x height)

1/2 x 2 x 3= 3

there are 4 triangles, area of both triangles = 3x4 = 12

Area of rectangle = length x width

Area of middle rectangle = 6 x 7 = 42

Area of two side rectangles = (3 +3) x 7 = 42

surface area = 42 + 42 + 12 = 96

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like why are we still alive or why are we still on the site?

Step-by-step explanation:

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PLS HELP ILL MARK CROWN
jok3333 [9.3K]

Answer:

4x−7

Step-by-step explanation:

Being given our polynomial:

4x^{2}+ x - 14,

We must find the roots to get our answer.

x = (- 1 ± √(1 - 4*4*(-14)) / 8

x = (- 1 ± √225) / 8

x = ( -1 ± 15) / 8

x₁ = (- 1 + 15)/ 8 = 14/8 = 7 / 4

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The factors we came up with:

(x - x₁)(x - x₂)

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The correct option is C.

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Last year 64 new houses were built in a neighborhood so far this year 7/8 of them have been sold how many new houses have been s
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Answer:

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Step-by-step explanation:

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6 0
2 years ago
There are three boxes: one with two golden coins, one with two silver coins, and one with one golden coin and one silver coin. A
krek1111 [17]

Answer:

Step-by-step explanation:

From Bayes' theorem is stated mathematically as the following equation:[2]

{\displaystyle P(A\mid B)={\frac {P(B\mid A)\,P(A)}{P(B)}},}

where A and B are events and P(B) ≠ 0.

P(A) and P(B) are the probabilities of observing A and B without regard to each other.

P(A | B), a conditional probability, is the probability of observing event A given that B is true.

P(B | A) is the probability of observing event B given that A is true.

At this point, go through the attached file before you continue with part B.

Part B)

P(silver) = P(silver from SS)+P(silver from GS)

note P(SS)=P(GG)=P(GS) = 1/3

P(silver from SS) = 1

P(silver from GS) = 1/2

hence

P(Silver from SS) = 1/3

P(Silver from GS) = 1/3 *1/2

P(Silver) = 1/3*1+1/3*1/2

required probability = P(Silver from SS)/P(Silver) = 2/3

4 0
3 years ago
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