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prisoha [69]
3 years ago
9

Harmony earns a \$42{,}000$42,000dollar sign, 42, comma, 000 salary in the first year of her career. Each year, she gets a 4\%4%

4, percent raise.
Which expression gives the total amount Harmony has earned in her first nnn years of her career?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
42{,}000\left(\dfrac{1-0.04^n}{0.96}\right)42,000(
0.96
1−0.04
n

​
)42, comma, 000, left parenthesis, start fraction, 1, minus, 0, point, 04, start superscript, n, end superscript, divided by, 0, point, 96, end fraction, right parenthesis

(Choice B)
B
42{,}000\left(\dfrac{1-1.04^n}{-0.04}\right)42,000(
−0.04
1−1.04
n

​
)42, comma, 000, left parenthesis, start fraction, 1, minus, 1, point, 04, start superscript, n, end superscript, divided by, minus, 0, point, 04, end fraction, right parenthesis

(Choice C)
C
42{,}000\left(\dfrac{1-1.04^n}{0.96}\right)42,000(
0.96
1−1.04
n

​
)42, comma, 000, left parenthesis, start fraction, 1, minus, 1, point, 04, start superscript, n, end superscript, divided by, 0, point, 96, end fraction, right parenthesis

(Choice D)
D
42{,}000\left(\dfrac{1-0.96^n}{-0.04}\right)42,000(
−0.04
1−0.96
n

​
)
Mathematics
1 answer:
grandymaker [24]3 years ago
6 0

Answer:

A=42000(1.04)^n

Step-by-step explanation:

This is a compound interest formula expressed as:

A=P(1+i)^n

Where:

  • n is time in years
  • i is the rate of interest
  • A is the accumulated amount after n years
  • P is the initial amount.

#We substitute the given values to determine amount after n years as follows:

A=P(1+i)^n\\\\=42000(1+0.04)^n\\\\=42000(1.04)^n

Hence, the amount earned after n years is given by the expression A=42000(1.04)^n

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Step-by-step explanation:

Total outcomes possible: 36

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Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

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Probability of an event E can be formulated as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A)  = \dfrac{12}{36} = \dfrac{1}{3}

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)}  Count 1

Possible cases for sum 3: {(1,2), (2,1)}  Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)}  Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)}  Count 4

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P(B)  = \dfrac{15}{36} = \dfrac{5}{12}

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P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}

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Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

P(A \cap B) = \dfrac{7}{\text{36}}

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