Question

If square root of x has a decimal approximation of 3.4, then x is between which two integers? In your final answer, include all calculations.

Answer 1

Answer:

The integers between which x lies is:

11 and 12

Step-by-step explanation:

square root of x has a decimal approximation of 3.4

i.e. $\sqrt{x}=3.4$

We have to find the integers between which x lies

$\sqrt{x}=3.4$

On squaring both sides, we get

$x=3.4^2$

x=11.56

Clearly, 11.56 lies between 11 and 12

Hence, the integers between which x lies is:

11 and 12

Answer 2

Answer:

You know that √x = 3.4, therefore x = 3.4² = 11.56

Hope I helped :)