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3 years ago

What is the product of the two solutions from the quadratic formula?

Mathematics

1 answer:

ollegr [7]3 years ago

5 0

Answer:

c/a

Step-by-step explanation:

The product of two solutions from the quadratic formula is c/a.

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What is the solution of the system x − 3y = –13 and 5x + 7y = 34? A. `x = (6)/(5)`, y = 4 B. `x = (7)/(2), y = (9)/(2)` C. `x =

Masteriza [31]

For this case we have the following system of equations:

$x-3y = -13\\5x + 7y = 34$

From the first equation we clear "x":

$x = -13 + 3y$

We substitute in the second equation:

$5 (-13 + 3y) + 7y = 34$

We apply distributive property:

$-65 + 15y + 7y = 34$

We add similar terms:

$-65 + 22y = 34$

We add 65 to both sides:

$22y = 34 + 65\\22y = 99$

We divide between 22 on both sides:

$y = \frac {99} {22}\\y = \frac {9} {2}$

We look for the value of the variable "x":

$x = -13 + 3 \frac {9} {2}\\x = -13 + \frac {27} {2}\\x = \frac {-26 + 27} {2}\\x = \frac {1} {2}$

Thus, the solution of the system is:

$(x, y): (\frac {1} {2}, \frac {9} {2})$

ANswer:

$(x, y): (\frac {1} {2}, \frac {9} {2})$

5 0

3 years ago

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Find the volume of the cone.

Contact [7]

<em>V</em>≈301.59

I think this is the answer.

Hope this helps!

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3 years ago

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Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

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3 years ago

-1 - 5 (-2k+3)= -76

disa [49]

Answer:

k= -6

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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The picture shows 3 triangles. Triangle 2 and Triangle 3 are images of Triangle 1 under

ch4aika [34]

The side lengths are the same.
Step-by-step explanation:
A rigid transformation does not change any dimensions. The side lengths are the same.

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2 years ago