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Korolek [52]
3 years ago
7

Write sin 33° in terms of cosine

Mathematics
2 answers:
ycow [4]3 years ago
4 0

Answer:  \sin 33^\circ=\cos 57^\circ.

Step-by-step explanation:  We are given to write sin 33° in terms of cosine.

We know that

The sine of any acute angle is equal to the cosine of its complement.

Now, the complement of an acute angle with measurement 33° is given by

90^\circ-33^\circ=57^\circ.

Therefore, the sine of an angle with measurement 33° is equal to the cosine of an angle with measurement 57°.

Thus, we can write as follows :

\sin 33^\circ=\cos 57^\circ.

Hence, \sin 33^\circ=\cos 57^\circ.

Greeley [361]3 years ago
3 0
Cos 57 it has to add up to 90
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kherson [118]

Answer:

brainliest answer

Step-by-step explanation:

10-2=8 constants

-x+8 simplified

3 0
3 years ago
you bought 12 two liter bottles of coke and sprite for the chridtmas dance the coke was on sale for 1.00 per bottle and the Spri
AlladinOne [14]

Answer:

6 of each

Step-by-step explanation:

1.50 x 6= 9

1 x 6= 6

9+6=15

6 0
3 years ago
Determine the unknown angle measures in the figure.<br><br>HELP NOW!!! please
maw [93]

Answer:

m∠1=80°

m∠2=112°

m∠3=131°

m∠4=80°

m∠5=37°

Step-by-step explanation:

First you have to find m∠2

To do that find m∠6 (I created this angle shown in pic below)

Find m∠6 by using the sum of all ∠'s in a Δ theorem

m∠6=180°-(63°+49°)

m∠6=68°

Now you can find m∠2 with the supplementary ∠'s theorem

m∠2=180°-68°

m∠2=112°

Then you find m∠5 using the sum of all ∠'s in a Δ theorem

m∠5=180°-(112°+31°)

m∠5=37°

Now you can find m∠1

m∠1=180°-(63°+37°)

m∠1=180°-100°=80°

m∠4 can easily be found too now:

m∠4=180°-(63°+37°)

m∠4=80°

m∠3=180°-49°

m∠3=131°

8 0
3 years ago
Solve this system of equations algebraically: y x = 19 – x2 x y = 80 1. Isolate one variable in the system of equations. Y = –x2
miskamm [114]

System of equations helps to solve real-life problems. The system of equations will not have no solution.

<h3>What is a System of the equation?</h3>

Inconsistent System

A system of equations to have no real solution, the lines of the equations must be parallel to each other.

Consistent System

1. Dependent Consistent System

A system of the equation to be Dependent Consistent System the system must have multiple solutions for which the lines of the equation must be coinciding.

2. Independent Consistent System

A system of the equation to be Independent Consistent System the system must have one unique solution for which the lines of the equation must intersect at a particular.

The two of the system of equations given to us are,

y+x=19-x^2

x+y = 80

Now,

1. The first step is to isolate one variable in the system of equations,

y=19-x^2-x

y=80-x

2. The second step is to substitution to create a one-variable equation.

80-x=19-x^2-x\\x^2-x+x=19-80\\x^2 = -61

Now, since the value of x  is the negative square root. therefore, the system of equations will not have a real number of solutions.

If we plot the two equations on the graph, then the line of the system of equations will not intersect any point, therefore, the system of equations will have no solution.

Hence, the system of equations will not have no solution.

Learn more about the System of the equation:

brainly.com/question/12895249

6 0
3 years ago
2!<br> a) 1<br> b) 2<br> c) 4<br> d) 0
Monica [59]

Answer:

if Im not mistaken it is 2

Step-by-step explanation:

2! Is the same thing as 2*1 and 2*1 is 2, so technically for factorials the higher in number you get you have to multiply all the numbers going back to one

5 0
3 years ago
Read 2 more answers
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