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3 years ago

Please help me with problem

Mathematics

1 answer:

Alexus [3.1K]3 years ago

8 0

Okay. The square root of 2 is between the square root of 1 and 4, which is greater than 1, but less than 2. In decimal form, that is about 1.41, which is greater than 1.4. 3/4 (0.75) is less than 0.7575757575, because 3/4 terminated, while the other decimal repeats. With that being said, here are the numbers ordered from least to greatest.

3/4, .75 decimal repeating, 1.4, square root of 2

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Answer:

Given System of equation:

x-y =6 .....,[1]

2x-3z = 16 ......[2]

2y+z = 4 .......[3]

Rewrite the equation [1] as

y = x - 6 .......[4]

Substitute the value of [4] in [3], we get

$2(x-6)+z = 4$

Using distributive property on LHS ( i.e, $a \cdot (b+c) =a \cdot b+ b \cdot c$ )

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2x - 12 +z =4

Add 12 to both sides of an equation:

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Simplify:

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On substituting equation [2] in [5] we get;

2x+z=2x -3z

z = -3z

Add 3z both sides of an equation:

z+3z = -3z+3z

4z = 0

Simplify:

z = 0

Substitute the value of z = 0 in [2] to solve for x;

$2x-3(0) = 16$

2x = 16

Divide by 2 both sides of an equation:

$\frac{2x}{2} =\frac{16}{2}$

Simplify:

x= 8

Substitute the value of x =8 in equation [4] to solve for y;

y = 8-6 = 2

y = 2

Therefore, the solution for the given system of equation is; x = 8 , y = 2 and z =0

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$\log_{(x-1)} 9=2$

the domain:
$x-1 >0 \ \land \ x-1 \not=1 \\
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the equation:
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The answer:
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***
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