Answer:
a) The speed of the slider is 4.28 in/s
b) The velocity vector is 2.33 in/s
Explanation:
a) According to the diagram 1 in the attached image:
Also:
![v_{C} =v_{A}+w_{AC}*r_{C/A}\\v_{Ci}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC} \\6.883&-9.829&0\end{array}\right]\\v_{Ci}=-3j+(0+9.829w_{AC} i-(0-6.883w_{AC})j\\v_{Ci}=9.829w_{AC}i+(-3+6.883w_{AC})j](https://tex.z-dn.net/?f=v_%7BC%7D%20%3Dv_%7BA%7D%2Bw_%7BAC%7D%2Ar_%7BC%2FA%7D%5C%5Cv_%7BCi%7D%3D-3j%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%260%26w_%7BAC%7D%20%5C%5C6.883%26-9.829%260%5Cend%7Barray%7D%5Cright%5D%5C%5Cv_%7BCi%7D%3D-3j%2B%280%2B9.829w_%7BAC%7D%20i-%280-6.883w_%7BAC%7D%29j%5C%5Cv_%7BCi%7D%3D9.829w_%7BAC%7Di%2B%28-3%2B6.883w_%7BAC%7D%29j)
If we comparing both sides of the expression:
b) According to the diagram 2 in the attached image:
![v_{C}=v_{A}+w_{AC}r_{C/A}\\v_{C}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC}\\7.713&-9.192&0\end{array}\right] \\v_{Ci}=-3j+(9.192w_{AC})i+7.713w_{AC}j\\v_{Ci}=9.192w_{AC}i+(7.713w_{AC}-3)j](https://tex.z-dn.net/?f=v_%7BC%7D%3Dv_%7BA%7D%2Bw_%7BAC%7Dr_%7BC%2FA%7D%5C%5Cv_%7BC%7D%3D-3j%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%260%26w_%7BAC%7D%5C%5C7.713%26-9.192%260%5Cend%7Barray%7D%5Cright%5D%20%5C%5Cv_%7BCi%7D%3D-3j%2B%289.192w_%7BAC%7D%29i%2B7.713w_%7BAC%7Dj%5C%5Cv_%7BCi%7D%3D9.192w_%7BAC%7Di%2B%287.713w_%7BAC%7D-3%29j)
Comparing both sides of the expression:
![v_{B}=v_{C}+w_{AC}r_{B/C}\\v_{B}=3.57i+\left[\begin{array}{ccc}i&j&k\\0&0&0.388\\-3.856&4.59&0\end{array}\right] \\v_{B}=3.57i+(0-1.78)i-(0+1.499)j\\v_{B}=1.787i-1.499j\\|v_{B}|=\sqrt{1.787^{2}+1.499^{2} } =2.33in/s](https://tex.z-dn.net/?f=v_%7BB%7D%3Dv_%7BC%7D%2Bw_%7BAC%7Dr_%7BB%2FC%7D%5C%5Cv_%7BB%7D%3D3.57i%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%260%260.388%5C%5C-3.856%264.59%260%5Cend%7Barray%7D%5Cright%5D%20%20%5C%5Cv_%7BB%7D%3D3.57i%2B%280-1.78%29i-%280%2B1.499%29j%5C%5Cv_%7BB%7D%3D1.787i-1.499j%5C%5C%7Cv_%7BB%7D%7C%3D%5Csqrt%7B1.787%5E%7B2%7D%2B1.499%5E%7B2%7D%20%20%7D%20%3D2.33in%2Fs)
Answer:
When work is positive, the environment does work on an object.
Explanation:
According to the work-energy theorem, the net work done by the forces on a body or an object is equal to the change produced in the kinetic energy of the body or an object.
The concept that summarizes a concept related to the work-energy theorem is that ''When work is positive, the environment does work on an object.''
Object B is positively charged, Object C is negatively charged, Object D is negatively charged.
Some guidance notes which may help.To calculate the current flow, Ohm's law can be used. This can be written as current=voltage/resistance, or I=V/R. V is 1.5V.R for the copper wire quoted would be calculated as R = resistivity x length/cross sectional area. The area would be calculated from the formula area = pi x diameter squared/4So, R=resistivity x length divided by (pi x diameter squared/4)Until is the resistivity of copper is known, that's about as far as can be gone.Any further questions, please ask.
