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BabaBlast [244]
3 years ago
9

When do both hemispheres receive the same amount of the sun's energy?

Physics
1 answer:
Rasek [7]3 years ago
8 0

Answer:

Both hemispheres receive the same amount of sunlight during <em>both autumnal equinox and vernal equinox </em>

Explanation:

The vernal or spring equinox happens around March 20 or thereabouts yearly. Equinoxes and various seasons happen as the Earth orbits the Sun and the Earth's orbit. Thus, we have Autumn equinox and spring or vernal equinox. During the Northern hemisphere spring and summer, the northern hemisphere is tilted towards the sun while during the Autumn and winter the northern hemisphere is tilted away from the sun.

During the autumn and spring equinoxes, the earth is neither tilted away or towards the sun. This means that both northern and southern hemisphere receive equal sunlight during these periods: that is hours of daylight and night are roughly about the same.

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A student standing on a stationary skateboard tosses a textbook with a mass of mb = 1.35 kg to a friend standing in front of him
nataly862011 [7]

Answer:

a) u_c=0\ m.s^{-1}       &        m_c.v_c=m_b.v_b\times \cos\theta

b) v_c=0.0566\ m.s^{-1}

c) p_e=2.9218\ kg.m.s^{-1}

Explanation:

Given:

mass of the book, m_b=1.35\ kg

combined mass of the student and the skateboard, m_c=97\ kg

initial velocity of the book, v_b=4.61\ m.s^{-1}

angle of projection of the book from the horizontal, \theta=28^{\circ}

a)

velocity of the student before throwing the book:

Since the student is initially at rest and no net force acts on the student so it remains in rest according to the Newton's first law of motion.

u_c=0\ m.s^{-1}

where:

u_c= initial velocity of the student

velocity of the student after throwing the book:

Since the student applies a force on the book while throwing it and the student standing on the skate will an elastic collision like situation on throwing the book.

m_c.v_c=m_b.v_b\times \cos\theta

where:

v_c= final velcotiy of the student after throwing the book

b)

m_c.v_c=m_b.v_b\times \cos\theta

97\times v_c=1.35\times 4.61\cos28

v_c=0.0566\ m.s^{-1}

c)

Since there is no movement of the student in the vertical direction, so the total momentum transfer to the earth will be equal to the momentum of the book in vertical direction.

p_e=m_b.v_b\sin\theta

p_e=1.35\times 4.61\times \sin28^{\circ}

p_e=2.9218\ kg.m.s^{-1}

6 0
3 years ago
Which of the following is true about Viscosity of liquids:
White raven [17]
Viscosity of liquids is essentially the 'thickness' of the liquid. For instance, honey and water have different viscosities. Honey has a higher one and therefore, liquids with high viscosity do not flow as well as liquids with low viscosity (water).
4 0
3 years ago
Read 2 more answers
Fraunhofer single slit explanation
12345 [234]

Answer:

This is an attempt to more clearly visualize the nature of single slit diffraction. The phenomenon of diffraction involves the spreading out of waves past openings which are on the order of the wavelength of the wave.

Explanation:

4 0
3 years ago
if you have a mass of 55 kg and you are standing 3 meters away from your car, which has a mass of 1234 kg, how strong is the for
bagirrra123 [75]

Gravitational force between two masses is given by formula

F = \frac{Gm_1m_2}{r^2}

here we know that

m_1 = 55 kg

m_2 = 1234 kg

r = 3 m

G = 6.67 \times 10^{-11} Nm^2/kg^2

now from the above equation we will have

F = \frac{(6.67 \times 10^{-11})(55)(1234)}{3^2}

F = 5.03 \times 10^{-7}N

so above is the gravitational force between car and the person

5 0
3 years ago
How do i do a Wavelength and frequency problem
KengaRu [80]

Answer:

wavelength = v/f or wavelength equals to velocity over frequency

frequency= v/w or velocity over wavelength

frequency= 1/p or one over period or time

7 0
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