Hi,
To convert 3 days to seconds write this.
1h = 3600s
24h = 3600 · 24 = 86400
3 days = 3 · 86400 = 259200sec
Hope this helps.
r3t40
Volume=mass/density
volume=455.6/19.3
volume=23.6 mL
Answer:
112 m/s², 79.1°
Explanation:
In the x direction, given:
x₀ = 0 m
x = 19,500 cos 32.0° m
v₀ = 1810 cos 20.0° m/s
t = 9.20 s
Find: a
x = x₀ + v₀ t + ½ at²
19,500 cos 32.0° = 0 + (1810 cos 20.0°) (9.20) + ½ a (9.20)²
a = 21.01 m/s²
In the y direction, given:
y₀ = 0 m
y = 19,500 sin 32.0° m
v₀ = 1810 sin 20.0° m/s
t = 9.20 s
Find: a
y = y₀ + v₀ t + ½ at²
19,500 sin 32.0° = 0 + (1810 sin 20.0°) (9.20) + ½ a (9.20)²
a = 109.6 m/s²
The magnitude of the acceleration is:
a² = ax² + ay²
a² = (21.01)² + (109.6)²
a = 112 m/s²
And the direction is:
θ = atan(ay / ax)
θ = atan(109.6 / 21.01)
θ = 79.1°
Answer:
638 m.
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 94 m/s
Final velocity (v) = 22 m/s
Time (t) = 11 s
Distance (s) =?
We can obtain the distance travelled by using the following formula:
s = (u + v) t /2
s = (94 + 22) × 11 /2
s = 116 × 11 /2
s = 1276 /2
s = 638 m
Thus, the distance travelled is 638 m.
<h2>
Option 3, 216 m is the correct answer.</h2>
Explanation:
We have initial velocity, u = 15 m/s
Time, t = 12 seconds
Final velocity, v = 21 m/s
We have equation of motion v = u + at
Substituting
21 = 15 + a x 12
a = 0.5 m/s²
Now we have equation of motion v² = u² + 2as
21² = 15² + 2 x 0.5 x s
s = 216 m
Displacement = 216 m
Option 3, 216 m is the correct answer.
