Ok , with that information we can write the equations
x + y = 6
5x + 4y = 28
Where x = how many people ordered chicken
and y = how many people ordered egg salad
Through elimination , we can set one of the variables in both equations equal so we can eliminate it :
(4)x + (4)y = (4)6
5x + 4y = 28
4x + 4y = 24. equation 1
5x + 4y = 28. equation 2
Now we can subtract the second equation by the first equation and isolate one variable:
equation 2 - equation 1
5x - 4x + 4y - 4y = 28 - 24
x = 4
Now that we discovered our x value ( How many people ordered chicken salad ) , we can apply it to one of the equations and discover y ( how many people ordered egg salad)
x + y = 6
x= 4
4 + y = 6
We can shift 4 to the other side of the equation by subtracting 4 from both sides of the equation:
4 - 4 + y = 6 - 4
y = 2
x=4 and y=2
So the awnser is :
4 people ordered chicken salad and 2 people ordered egg salad!
I hope you understood my brief explanation!!
p.s if you want to know how to use another method to solve these problems ( Substition) , just let me know in a comentary down here
Answer:
40 degree acute
Step-by-step explanation:
1. 8c^2-26c+15= (4c-3) (2c-5). Break the expression into groups: =(8c^2-6c)+(-20c+15). Factor out 8c^2-6c: 2c(4c-3). Factor out -5 from -20c+ 15: -5(4c-3). Lastly factor out common term (4c-3) and thats how you'll get your answer (4c-3) (2c-5).
2. common factors for 270 and 360 is 90.To find this write the factors of each and find the largest one.270: 1, 270, 2, 135, 3, 90, 5, 54, 6, 45, 9, 30, 10, 27, 15, 18360: 1, 360, 2, 180, 3, 120, 4, 90, 5, 72, 6, 60, 8, 45, 9, 40, 10, 36, 12, 30, 15, 24, 18, 20
3. The factors for 8 a3b2 and 12 ab4 is 4. because 8: 1, 2, 4, 812: 1, 2, 3, 4, 6, 12.
4. 81a^2+36a+4= (9a+2)^2. Break down the expression into groups: (81a^2+18a)+(18a+4). Factor out 9a from 81a^2 +18a: 9a(9a+2). Factor out 2 from 18a+4: 2(9a+2). so the groups you got are now 9a(9a+2)+2(9a+2). Lastley factor out common term (9a+2) to get (9a+2) (9a+2). Finally you get the answer (9a+2)^2.
5. mn-15+3m-5n= (n+3)(m-5). factor out m from nm+3m: m(n+3). Factor out -5 from -5n-15: -5(n+3). And thats how you get the number (n+3)(m-5)
Hope this helped :) Have a great day
Answer:
The solutions are the following:
- z=2(cos(π6)+isin(π6))=√3+12i
- z=2(cos(2π3)+isin(2π3))=−1+i√3
- z=2(cos(7π6)+isin(7π6))=−√3−12i
- z=2(cos(5π3)+isin(5π3))=1−i√3
<em>hope this helps!! :) --Siveth</em>