The number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
- Since one student runs at a speed of 180 feet per minutes, in time t minutes, he moves a distance of d = 180t.
- Also, the second student runs at a speed of 160 feet per minute, in time t minutes, he moves a distance of d' = 160t.
Since they are initially 10 feet apart, their total distance apart after t minutes is D = d + 10 + d'
D = 180t + 10 + 160t
D = 340t + 10
<h3>Number of minutes before they are 1870 feet</h3>
Making t subject of the formula, we have
t = (D - 10)/340
Since they are 1870 feet apart after t minutes, D = 1870 feet.
t = (D - 10)/340
t = (1870 - 10)/340
t = 1860/340
t = 5.47 minutes
So, the number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
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Answer:
the answer is a) 37.125
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Answer:
24 bars of treasure
Step-by-step explanation:
You just need to do the opposite in order to find the total value since you divided the treasure up we need to multiply the treasure “back”.
3 buried bars is equal to 1/3 of the remaining treasure. Multiply by 3 to get 3/3 or 100% of buried and crew portion. So we now have 9 bars. Then multiply by 2 to get 100% of what was given to bill, crew and buried. We now have 18 bars. Then we know that we took 1/4 for ourselves so that means 18 bars represents 3/4 of the treasure. So when we look at factors of 18 we find that 3 x 6 = 18 and 4 x 6 = 24 so we conclude that we had 24 bars of treasure before the split.
If i was you i would look up every box in the word bank then find examples of each box and do the best I could.
-hope this helps!
Answer:
Step-by-step explanation: see attachment below
