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Mumz [18]
3 years ago
11

A baker has 5 1/4 pies in her shop. She cut the pies in pieces that are each 1/8 of a whole pie.

Mathematics
2 answers:
Inessa05 [86]3 years ago
8 0
Knowing that 1 = 8/8
this means 5 = 40/8
1/4 = 2/8

add 40/8 + 2/8 to get 42/8

this means she will have 42 pieces of pie
vlabodo [156]3 years ago
8 0

Answer:

42  pieces of pie a baker have .

Step-by-step explanation:

As given

A\ baker\ has\ 5 \frac{1}{4}\ pies\ in\ her\ shop.

i.e

A\ baker\ has\ \frac{21}{4}\ pies\ in\ her\ shop.

She\ cut\ the\ pies\ in\ pieces\ that\ are\ each\ \frac{1}{8}\ of\ a\ whole\ pie.

Than the equation becomes

Let us assume that the number of  pieces of pie a baker have = x

\frac{21}{4} = \frac{1\times x}{8}

Simplify the above

\frac{21\times 8}{4} = x

21\times 2 = x

42 = x

Therefore 42  pieces of pie a baker have .

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PLS HELP ME!!! The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of
Pachacha [2.7K]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

What is the approximate volume of this figure?

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{V = 334.93\:cm^3 \to Volume\:of\:the\:figure \approx 335\:cm^3 }}}\end{array}}\qquad\quad\checkmark

Answer:

The volume of the figure is approximately 335 cm³

_______________________

I Hope this helps, greetings ... Dexteright02! =)

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3 years ago
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