For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8
Answer:
just go on desmos graphing calculator and type it in
Step-by-step explanation:
Answer:
It's legit just 5.9600000000000000000000000000000000000000000.
Well, luckily it is apparent that (x-1) is a root because when x=1 the equation is equal to zero. So we can divide the equation by that factor to find the other roots.
(2x^3+9x^2+4x-15)/(x-1)
2x^2 r 11x^2+4x-15
11x r 15x-15
15 r 0
(x-1)(2x^2+11x+15)=0
(x-1)(2x^2+6x+5x+15)=0
(x-1)(2x(x+3)+5(x+3))=0
(x-1)(2x+5)(x+3)=0
So the roots are x= -3, -2.5, 1
Answer:
i hate my self infinity times