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3 years ago

Graphs of functions on the interval [−4, 4] are depicted below. For each function, find:

Mathematics

1 answer:

DENIUS [597]3 years ago

4 0

Answer:

a) The domain is the set of the possible values of x.

In the graph, we can see that x goes from - 4 to 4

So the domain is: D = x∈ {-4, 4)

b) The zeros are the points where the graph cuts the x-axis.

Those values are:

x = -2

x = 0

x = 2.

c) The graph is positive if it is above the x-axis and it is negative if it is below the x-axis.

in the interval {-4,0} the graph is bellow the x-axis, so in this interval the function is negative.

in the interval {0, 2} the graph is above the x-axis, so in this interval the function is positive.

in the interval {2, 4} the graph is bellow the x-axis, so in this interval the function is negative.

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Inga [223]

Answer:

W = X in.

L = (3x - 6) in.

A = L*W = (3x-6)X = 45,

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Solution Set: x = 5, and x = -3.

Select + value of X:

x = 5

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Step-by-step explanation:

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2 years ago

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Anna11 [10]

Answer:

Step-by-step explanation:

For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.

Also, two physically quantities can only be added or subtracted only when their dimension are same.

here all option are dimensionally correct except the 5th option where

dimension of t= [T] whereas dimension of a/v is $\frac{LT^{-2}}{LT^{-1}}$

= T^{-1}

since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.

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3 years ago

What is the area of the square adjacent to the third side of the triangle?

Naddik [55]

Answer:

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and

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Step-by-step explanation:

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