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devlian [24]
3 years ago
10

If f(x) = x over 2 + 8, what is f(x) when x = 10?

Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

f(10) = 13

Step-by-step explanation:

f(x) = x/2 + 8

Let x = 10

f(10) = 10/2 +8

f(10) = 5+8

f(10) = 13

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The sum of eleven and a number is negative nine.
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What is the measure of ∠H? <br>1. 115<br>2. 65<br>3. 50<br>4. 25
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2

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2 years ago
Which expression is equivalent
gtnhenbr [62]

Answer:

Option  B is correct.

\frac{81m^2n^5}{8} is equivalent to \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Step-by-step explanation:

Given expression: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Using exponents power:

  • (ab)^n = a^nb^n
  • (a^n)^m = a^{nm}
  • a^m \cdot a^n = a^{m+n}

Given: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Apply exponent power :

⇒ \frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}

⇒ \frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}

⇒\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}

Therefore, the expression which is equivalent to  \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3} is,  \frac{81m^2 n^5}{8}

4 0
3 years ago
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Sonbull [250]

Answer:

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Step-by-step explanation:

Distributive property is when you distribute the values in a parenthesis with the outside multiplying factor

2*(5+7)= 2*5 + 2*7

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24 = 24

distributive property holds true

4 0
3 years ago
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