How many significant figures does the value 43.023 have?

tatiyna

Answer: y = -4x - 4

Step-by-step explanation:

Point slope form: y - y1 = m(x - x1)

Plug in y1 and x1, and m. M is the slope, x1 and y1 are the values for a coordinate. You don't need to plug anything in for y or x, just y1 and x1.

First, find the slope. To find the slope, use this "formula" : $slope=\frac{rise}{run} =\frac{y1-y2}{x2-x1}$

Find two coordinate points. Let's use (-2,4) and (0,-4). Based on this, we know that y1 is 4, y2 is -4, x1 is -2, and x2 is 0. Plug these into the formula:

$\frac{4--4}{-2-0} =\frac{4+4}{-2} =\frac{8}{-2}=-4$

Then, pick any point to plug into the equation. Let's use (0,-4)

Finally, plug everything into the equation:

y - - 4 = -4(x - 0)

y + 4 = -4x

y = -4x - 4

3 0

3 years ago

Read 2 more answers

I need help finding ac, cb, and ab

Taya2010 [7]

AC is 2x+1
CB is 3x-4
AB= 2x+1+3x-4

6 0

3 years ago

Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago

Not enough INFO sas sss

shepuryov [24]

$\huge \bf༆ Answer ༄$

The given triangles are similar by ~

$\textsf{SSS criteria }$

8 0

3 years ago

Select the correct answer.

Elina [12.6K]

Answer:

A) 6.86×10⁴

Step-by-step explanation:

You want to write 68600 in scientific notation.

<h3>Expanded form</h3>

The number 68600 can be written in expanded form with exponents as ...

68600 = 6×10⁴ +8×10³ +6×10² +0×10¹ +0×10⁰

The left-most term of this sum tells you the exponent in scientific notation:

68600 = 6.86×10⁴

5 0

1 year ago