The following are the temperatures in °C for the first 10 days in January:
1 answer:
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Answer:
the graph on the right-top
Step-by-step explanation:
Transferring an "x" to the right side in , we get
The system of inequalities is
We have y=2x+2 - ascending function with a=2, b=2
b=2 shows that ascending function intersects Y-axis is in y=2 - that situation is only on the right-top and left-down. So, we refuse left-top and right-down.
y=-x-3 - descending function with a=-1, b=-3
y<2x+2 is an area below the ascending function and we see that on the left-
is an area above the descending function
On the left-down we have an area above both functions, so we refuse this picture
Right-top is correct
Integration will be ln | ( x /9 ) + ( ) | + c .
Given ∫ 1 dx / ( - 81 )
Put ,
x = 9 secθ
dx = 9 secθ tanθ dθ
and
= 9 tanθ
Substituting values in ∫ 1 dx / ( - 81 ) ,
∫ (9 secθ tanθ ) dθ / ( 9 tanθ )
∫ secθ dθ = ln | secθ + tanθ | + c
= ln | ( x /9 ) + ( / 9 ) | + c
= ln | ( x /9 ) + ( ) | + c
Hence , the integration will be ln | ( x /9 ) + ( ) | + c .
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