Answer:
x=amount invested at 7%
2x=amount invested at 8%
3x=amount invested at 9%
interest=principal*rate*time (time=1 year)
$150=0.07x+0.08*2x+0.09*3x
$150=0.07x+0.16x+0.27x
$150=0.50x
$1500=5x
x=$300 invested at 7%
2x=$600 invested at 8%
3x=$900 invested at 9%
Step-by-step explanation:
Answer:
289
Step-by-step explanation:
Raise 17 to the power of 2
Is this what you are asking for
I can't see the picture, can you please explain the problem in the comment bar below this so can edit my answer to help?
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
Answer:
4,600
Step-by-step explanation:
1,200+1,200+1,100+1,100
