Consider the ammonolysis of benzoyl chloride by adding concentrated ammonium hydroxide to form the final product, benzamide. Rea
ction scheme of benzoyl chloride with cold, conc. ammonium hydroxide over ther reaction arrow, and benzamide, hydrochloric acid, and water as products. Calculate the molar mass of the reactant and product. Report molar masses to 1 decimal place. Molar mass of benzoyl chloride g / mol Molar mass of benzamide g / mol
1 answer:
You might be interested in
Answer:
molality of sodium ions is 1.473 m
Explanation:
Molarity is moles of solute per litre of solution
Molality is moles of solute per kg of solvent.
The volume of solution = 1 L
The mass of solution = volume X density = 1000mL X 1.43 = 1430 grams
The mass of solute = moles X molar mass of sodium phosphate = 0.65X164
mass of solute = 106.6 grams
the mass of solvent = 1430 - 106.6 = 1323.4 grams = 1.3234 Kg
the molality =
Thus molality of sodium phosphate is 0.491 m
Each sodium phosphate of molecule will give three sodium ions.
Thus molality of sodium ions = 3 X 0.491 = 1.473 m