Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K
Explanation :
We have to calculate the entropy change of reaction
.

![\Delta S^o=[n_{NH_3}\times \Delta S^0_{(NH_3)}]-[n_{N_2}\times \Delta S^0_{(N_2)}+n_{H_2}\times \Delta S^0_{(H_2)}]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo%3D%5Bn_%7BNH_3%7D%5Ctimes%20%5CDelta%20S%5E0_%7B%28NH_3%29%7D%5D-%5Bn_%7BN_2%7D%5Ctimes%20%5CDelta%20S%5E0_%7B%28N_2%29%7D%2Bn_%7BH_2%7D%5Ctimes%20%5CDelta%20S%5E0_%7B%28H_2%29%7D%5D)
where,
= entropy of reaction = ?
n = number of moles
= standard entropy of 
= standard entropy of 
= standard entropy of 
Now put all the given values in this expression, we get:
![\Delta S^o=[2mole\times (192.5J/K.mole)]-[1mole\times (191.5J/K.mole)+3mole\times (130.6J/K.mole)]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo%3D%5B2mole%5Ctimes%20%28192.5J%2FK.mole%29%5D-%5B1mole%5Ctimes%20%28191.5J%2FK.mole%29%2B3mole%5Ctimes%20%28130.6J%2FK.mole%29%5D)

Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K
The law of definite proportions agrees with Dalton atomic theory.
What is Dalton atomic theory?
It state that all matters is made of very tiny particles called atom. atoms are individual particles which can not be created or be destroyed in a chemical reactions. Atoms of given elements are identical in mass and chemical properties. Atoms of
different elements have different masses and chemical properties.
The law of definite proportions also known as proust's law ,state that a chemical compound contain the same proportion of elements by mass.this law is one of the stoichiometry .
Thus ,
This is the reason why it is agrees with dalton atomic theory.
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Answer: Volume would be 196.15 mL if the temperature were changed to
and the pressure to 1.25 atmospheres.
Explanation:
Given:
,
= 256 mL,
= 720 torr (1 torr = 0.00131579 atm) = 0.947368 atm
,
Formula used to calculate volume is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that the volume would be 196.15 mL if the temperature were changed to
and the pressure to 1.25 atmospheres.
Answer: 2 SO2 (g) + O2 (g) Kp = 7.69 If a vessel at this temperature initially ... and if the partial pressure of sulfur trioxide at equilibrium is 0.100 atm,
Explanation:
Answer:
yes, it is a homogeneous mixture because the different parts cannot be seen.
Explanation: