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daser333 [38]
3 years ago
5

What is the mass in grams of 4.91 moles of ammonium sulfate?

Chemistry
2 answers:
Montano1993 [528]3 years ago
4 0
1 mole is equal to 1 moles Ammonium Sulfate, or 132.13952 grams
Strike441 [17]3 years ago
4 0

Answer:

648.12g

Explanation:

First, we need to find the molar mass of ammonium sulphate (NH4)2SO4. This can be achieved by:

Molar Mass of (NH4)2SO4 = 2(14+4)+32+(4x16) = 132g/mol

Mass of (NH4)2SO4 = 4.91x132 = 648.12g

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3 years ago
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7 0
3 years ago
If 60 ml of naoh solution neutralizes 40 ml of 0.50 m h2so4, the concentration of the naoh solution is most nearly:
Bad White [126]
<span>The balanced chemical equation for this reaction is:

2NaOH (aq)+H2SO4 (aq) → Na2SO4 (aq)+2H2O (l)

According to question, 60 ml of NaOH solution was used for neutralizing 40 ml of 0.50M H2SO4.

The no. of moles of H2SO4 is calculated using the equation:
mol solute = (molarity) (L soln)

mol H2SO4 = 0.50 M x 0.040 L = 0.02 moles of H2SO4

As per the equation, the number of moles of NaOH used is:

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Therefore, using the given volume of NaOH, the concentration or molarity of NaOH can be calculated using the formula :

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