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ruslelena [56]
3 years ago
8

Which of the following atoms will have the same electron configuration?

Chemistry
1 answer:
chubhunter [2.5K]3 years ago
7 0

Answer:

I. N−3

III. F−1

Explanation:

A positive charge indicates a loss of electrons whereas a negative charge denotes electron gain.

For two species to have the same electron configuration, they must have the same number of electrons within their atomic space.

So, the solution to this problem will be two species with the same number of electrons:

    Nitrogen in neutral state has 7 electrons, on gaining 3 the electrons becomes 10

   Fluorine in neutral state has 9 electrons, on gaining 1 more, it will have 10 electrons.

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olganol [36]

Answer:

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

Explanation:

Step 1: Data given

Initial temperature = 10.0 °C

Final temperature = 25.0 °C

Energy required = 30000 J

Mass of the object = 40.0 grams

Step 2: Calculate the specific heat capacity of the object

Q = m* c * ΔT

⇒With Q = the heat required = 30000 J

⇒with m = the mass of the object = 40.0 grams

⇒with c = the specific heat capacity of the object = TO BE DETERMINED

⇒with ΔT = The change in temperature = T2 - T2 = 25.0 °C - 10.0°C = 15.0 °C

30000 J = 40.0 g * c * 15.0 °C

c = 30000 J / (40.0 g * 15.0 °C)

c = 50 J/g°C

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

3 0
3 years ago
Thủy phân este trong môi trường kiềm, thu được natri axetat và ancol metylic. công thức X là gì?
ValentinkaMS [17]

Correct option is B ethyl ethanoate

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<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em><em> ❤️</em>

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3 years ago
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sergiy2304 [10]
Ba3PO4 is not neutral, it is positive.  (NH4)2SO4 is neutral, the charges cancel.
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. MOLECULES that have an uneven pattern of electric charge (more positive in one area; more negative
kondaur [170]
They’re said to be
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2 years ago
What is the molar mass of potassium carbide. Please show me how you worked this out
solmaris [256]

Answer:

Answer. K2CO3 = 138 g/mol.

7 0
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