The concentration of the solution reduces and the number of moles of solute isn't affected.
Data;
- V1 = 50mL
- C1 = 12.0M
- V2 = 200mL
- C2 = ?
<h3>Facts about the diluted solution</h3>
1. When the solution is diluted, the concentration changes and this time, the concentration reduces.
Using dilution formula
The concentration of the solution reduces.
2. The number of moles remains the same.
When a solution is diluted, the number of moles remains the same because there's no change in the mass of the solute.
Learn more on concentration of a solution here;
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The overall balanced
chemical reaction for this is:
Detonation of
Nirtoglycerin <span>
4 C3H5N3O9 --> 12 CO2 + 6 N2 + O2 + 10 H2O </span>
Therefore:
2.00 mL x 1.592 g/mL =
3.184 g <span>
3.184 g / 227.1 /mol = 0.0140 mol nitroglycerin
4 moles --> 12 + 6 + 1 + 10 = 29 moles of gas
<span>0.0140 mol x (29/4) = 0.1017 moles of gases or (0.102 mol) </span></span>
The new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars. Details about pressure can be found below.
<h3>How to calculate pressure?</h3>
The pressure of a given gas can be calculated using the following formula:
P1/T1 = P2/T2
Where;
- P1 = initial pressure = 853.0 millibars
- P2 = final pressure = ?
- T1 = initial temperature = 29°C + 273 = 302K
- T2 = final temperature = 85°C + 273 = 358K
853/302 = P2/358
358 × 853 = 302P2
305374 = 302P2
P2 = 305374 ÷ 302
P2 = 1011.17 millibars
Therefore, the new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars.
Learn more about pressure at: brainly.com/question/15175692
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The value of Kc for the thermal decomposition of H₂S is 2.2 x 10⁻⁴ at 1400 K:
2 H₂S(g) ↔ 2 H₂(g) + S₂(g)
initial 3.5 M 0 0
at equilibrium 3.5 M - 2x 2x x
Kc = [S₂][H₂]² / [H₂S]²
2.2 X 10⁻⁴ = x(2x)² / (3.5 - 2x)²
2.2 x 10⁻⁴ = 4 x³ / (3.5)² Assuming x <<<<< 3.5
x = 0.088
Thus [H₂S] = 3.324 M
