The value of f(a)=4-2a+6
, f(a+h) is 
, [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6
.
Given a function f(x)=4-2x+6.
We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.
Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.
f(a)=4-2a+6 (By just putting x=a).
f(a+h)==
=4-2a-2h+6(
)
=4-2a-2h+6
=
[f(a+h)-f(a)]/h=[-(4-2a+6 )]/h
=
=
=6h+12a-2.
Hence the value of function f(a)=4-2a+6, f(a+h) is , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6.
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Answer:
Step-by-step explanation:
(g-f)(x) = 9x³ - 4x² + 10x - 55 - [ 4x³ +3x² - 5x + 20]
To remove the parenthesis, take - inside, multiply f(x) by -1
= 9x³ - 4x² + 10x - 55 - 4x³ - 3x² + 5x - 20
Now, bring like terms together,
= 9x³ - 4x³ - 4x² - 3x² + 10x + 5x - 55 - 20
= 5x³ - 7x² + 15x - 75
Answer:
so if you multiple4.8 percent by 3,000 u get 144 and then u divide by 3 and that u u 48 dollars per year
Answer:
- tn = 2097152 pennies
- tn = 20971.52 dollars.
Step-by-step explanation:
A surprisingly large amount of money.
The question is "Does the amount of money just double or do the previous amounts add to the present amount?"
I think it just doubles. Not only that, but she can't spend any of it until night 22 is reached.
- tn = a*2^(n - 1)
- a = 1 She starts with 1 penny.
- n = 22
- tn = 1*2^(22 - 1)
- tn = 1*2^21
- tn = 2097152 pennies
- tn = 20971.52 dollars.
