Fifty students were randomly selected to take part in a survey about their favorite school lunch. Each student was allowed to on
2 answers:
Answer:
The expected number of pizza servings is 270.
Step-by-step explanation:
Food Item Preferred Number of Students
pizza 27
cheeseburger 14
salad bar 9
Now we have been given that Fifty students were randomly selected to take part in a survey about their favorite school lunch. The school will be serving 500 lunches;
This means 10% of the total lunches or students were selected. So, if 27 students prefer pizza this means its 10 times will be needed for the whole lot making it pizzas.
Similarly, 140 cheeseburgers and 90 salad bars will be served making a tital of = lunches.
You might be interested in
If both triangles are similar the ratio of sides will be same
Answer: The graph in the bottom right-hand corner
(see figure 4 in the attached images below)
===========================================
Explanation:
Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.
Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.
After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.
