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aleksandr82 [10.1K]
3 years ago
9

Write the name of the period that has the digits 913

Mathematics
2 answers:
nikklg [1K]3 years ago
7 0
Units period also called the hundreds period
Bas_tet [7]3 years ago
5 0
Units period also called the hundreds period
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Maria solve the equation 34 equals X +19 although her final answer was correct she could’ve found it in a simpler way what is be
tankabanditka [31]
It would be
34 = x \ +  19
it would be 15 because you subtract 19 from both sides and the 19's cancel so your answer would be
x = 15
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Morgan is making two cookie recipes. Recipe A calls for one-third less than twice the number of cups of sugar than recipe B call
vredina [299]

Answer:

Step-by-step explanation:

2c-1/3=4 1/6

(1/3 x 2= 2/6)

2c= 3 5/6

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6 0
3 years ago
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Given cos theta = - 2/5 and sin theta < 0, find the six trigonometric values. I need help with this
Lena [83]

Answer:

\sin\,\theta =-\frac{\sqrt{21} }{5}

\tan\,\theta =\frac{\sqrt{21} }{2}

\sec\,\theta = \frac{-5}{2}

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\cot\,\theta =\frac{2}{\sqrt{21} }

Step-by-step explanation:

\cos\theta =\frac{-2}{5}

As both sin\,\theta,

\theta lies in the third quadrant.

In the third quadrant,

\sin\theta

\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}

\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}

\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}

\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }

\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }

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3 years ago
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kirill115 [55]
I'm pretty sure the answer is 2x2 + x -3
8 0
4 years ago
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I WILL MARK BRAINLIEST PLEASE HURRY
AfilCa [17]
Consider, pls, this explanation + solution:
according to the given equation the centre of this circle is in the poit (6;7) and its radius =4 units.
Using this data, it is possible to define right choice: D.

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