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3 years ago

12

An online music store is offering a promotion. When you spend $30 or more, you receive 3 songs for free. You Buy an album for $1

2 right and solve any quality that represents how much more money and we will spend to receive the three free songs

1 answer:

Lisa [10]3 years ago

3 0

Answer:

need to spend $18 more in addition to $12

Step-by-step explanation:

Given: According to online music store, if you spend $30 or more, you receive 3 songs for free

To find: How much more money need to be spend in addition to $12 to receive three free songs

Solution:

Let x denotes amount to be spend in addition to $12 to receive three free songs

According to question,

$x+12\geq 30\\x\geq 30-12\\x\geq 18$

You might be interested in

One Solution, infinitely many, or no solutions?<br><br>x-3y=27,2x=6y-14

sveta [45]

Ok, let’s take it step by step.
Take the first equation and solve for x.
x-3y=27
x=3y+27
Substitute x into the second equation.
2(3y+27)=6y-14
6y+68=6y-14
68=-14

Since 68 does not = -14, the system of equations has no solution.

8 0

4 years ago

Two bags each contain tickets numbered 1 to 10. John draws a ticket from each bag five times, replacing the tickets after each d

Serjik [45]

The amount or level of relationship between the tickets in the bags is

described by the correlation coefficient.

Response:

The correlation coefficient, <em>r</em> is approximately <u>0.75</u>

<u />

<h3>Method by which the correlation coefficient is obtained</h3>

Required:

Based on a similar question online, the value of the correlation coefficient, <em>r</em>, is to be determined.

The table of values is presented as follows;

$\begin{tabular}{c|c|c|}\underline{Draw}& \underline{ Bag 1}& \underline{Bag 2}\\Draw 1&2&4\\Draw 2&4&5\\Draw 3 &1&3\\Draw 4&6&4\\Draw 5&7&9\end{array}\right]$

The mean of the first bag, $\overline{x}_1$ = 4

Standard deviation of the first bag, s₁ = 2.5

Mean of the second bag, $\mathbf{\overline x_2}$ = 5

Standard deviation of the second bag, s₂ = 2.3

The sample size from each bag, <em>n</em> = 5

The given regression formula is presented as follows;

$\displaystyle r = \mathbf{ \frac{1}{n - 1} \cdot \sum \left(\frac{x - \overline x}{s_x} \right) \cdot \left(\frac{y - \overline{y}}{s_y} \right)}$

By calculation using the above data in the table on MS Excel, we have;

$\overline x_1$ = 4, s₁ = 2.54951

$\overline x_2$ = 5, s₂ = 2.345208

The following table of values can be calculated;

$\begin{array}{|c|c|c|c|}&\dfrac{x - \overline x_i}{s_x} & \dfrac{y - \overline y_i}{s_y} & \left(\dfrac{x - \overline x_i}{s_x} \right)\times \left(\dfrac{y - \overline y_i}{s_y} \right) \\&&& \\i = 1&-0.78446&-0.4264&0.334497\\i = 2&0&0&0\\i = 3&-1.1767&-0.8528&1.00349\\i = 4 &0.784464&-0.4264&-0.3345\\i = 5&1.176697&1.705606&\underline{2.006981}\\&&&\\ \ \sum ()&&&3.010471\end{array}\right]$

Therefore;

$\displaystyle \sum \left(\frac{x - \overline x}{s_x} \right) \cdot \left(\frac{y - \overline{y}}{s_y} \right) = \mathbf{ 3.010471}$

$\displaystyle r = \frac{1}{5-1} \times 3.010471 = 0.752618$

Rounding off to the nearest hundredth, we have;

The correlation coefficient, r ≈ <u>0.75</u>

<em>Possible question options are;</em>

<em>0.56</em>

<em>0.50</em>

<em>0.70</em>

<em>0.75</em>

Learn more about correlation coefficient here:

brainly.com/question/14753067

3 0

3 years ago

There are 482 studemts in the school and there are two Grade 4 classes: Ms.Ashley's and Mr.Ben's classes. Mrs. Aheley's class ha

Svetllana [295]

Answer:

<u>1. 45/482 of the students are in grade 4.</u>

<u>2. 5/9 of the students of the grade 4 are boys.</u>

<u>3. 7/15 of the grade 4 students are in Ms. Ashley's class</u>

<u>4. 3/4 of the students in Mr. Ben's class do not have siblings in the same school.</u>

<u>5. There are 14 students with glasses and 7 without glasses.</u>

Step-by-step explanation:

1. Let's review the information given to us for solving the questions:

Number of students in the school = 482

Ms. Ashley's Grade 4 class = 21 students

Ms. Ashley's Grade 4 class boys = 15 students

Ms. Ashley's Grade 4 class girls = 6 students

Ms. Ashley's Grade 4 class with glasses = 2/3 * 21 = 42/3 = 14 students

Mr. Ben's Grade 4 class = 24 students

Mr. Ben's Grade 4 class boys = 10 students

Mr. Ben's Grade 4 class girls = 14 students

Mr. Ben's Grade 4 class with siblings in the school = 1/4 * 24 = 24/4 = 6 students

2. Let's answer all the questions:

1. What fraction of the students in the school are in grade 4?

(Ms. Ashley's Grade 4 class + Mr. Ben's Grade 4 class)/ Number of students in the school

<u>21 + 24 / 482 = 45/482</u>

2. What fraction of the grade 4 students are boys?

(Ms. Ashley's Grade 4 boys + Mr. Ben's Grade 4 boys)/ (Ms. Ashley's Grade 4 class + Mr. Ben's Grade 4 class)

15 + 10 / 21 + 24

<u>25 / 45 = 5/9</u>

3. What fraction of the grade 4 students are in Ms. Ashley's class?

Ms. Ashley's Grade 4 class / (Ms. Ashley's Grade 4 class + Mr. Ben's Grade 4 class)

21 / 21 + 24

<u>21 / 45 = 7/15</u>

4. What fraction of the students in Mr. Ben's class that do not have siblings in the same school?

(Mr. Ben's Grade 4 class - Mr. Ben's Grade 4 class with siblings in the school)/ Mr. Ben's Grade 4 class

24 - 6 / 24

<u>18 / 24 = 3/4</u>

5. In Ms. Ashley's class, are there more students that wear glasses or do not wear glasses?

<u>There are 14 students with glasses and 7 without glasses.</u>

Note: Same answer to question 14038475, answered by me.

3 0

3 years ago

Can somebody help me out with this question?

Tresset [83]

#a

-2<0

$\\ \sf\longmapsto f(x)=x^2$

$\\ \sf\longmapsto f(-2)$

$\\ \sf\longmapsto (-2)^2$

$\\ \sf\longmapsto 4$

#b

0=0

$\\ \sf\longmapsto f(x)=2$

$\\ \sf\longmapsto f(0)=2$

#c

2>0

$\\ \sf\longmapsto f(x)=2x+1$

$\\ \sf\longmapsto f(2)$

$\\ \sf\longmapsto 2(2)+1$

$\\ \sf\longmapsto 4+1$

$\\ \sf\longmapsto 5$

4 0

3 years ago

Help please and as son as possible and thanks

lozanna [386]

The answer to 33 is 3. The answer to 37 is 9.

8 0

3 years ago