Answer:
![\boxed{\sf \ \ \ maximum \ is \ 11^9=2357947691 \ \ \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%5C%20%5C%20%5C%20maximum%20%5C%20is%20%5C%2011%5E9%3D2357947691%20%5C%20%5C%20%5C%20%7D)
Step-by-step explanation:
hello
![y = 11^{(6x-x^2)}=exp((6x-x^2)ln(11))](https://tex.z-dn.net/?f=y%20%3D%2011%5E%7B%286x-x%5E2%29%7D%3Dexp%28%286x-x%5E2%29ln%2811%29%29)
so to know the maximum to y we can check the maximum of
f(x)=![6x-x^2](https://tex.z-dn.net/?f=6x-x%5E2)
f is derivable and f'(x)=6-2x
f'(x)=0 <=> x = 3
so the maximum is reached for x = 3
f(3)=18-9=9
and then
![y = 11^9=2357947691](https://tex.z-dn.net/?f=y%20%3D%2011%5E9%3D2357947691)
to be rigorous, we can write the variation table of y to show that there is only one maximum
hope this helps
Answer:
39
Step-by-step explanation:
4 cubed is 64 and 64-25 is 39
Answer:
c. π
Step-by-step explanation:
Intgers, fractions, and repeating or finite-length decimals are all rational number.
Pi (π) is an irrational number.
Answer:
![n-3](https://tex.z-dn.net/?f=n%3C-10%2C%20%5C%3A%20n%3E-3)
Interval notation: ![(-\infty, -10)\cup(-3,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%20-10%29%5Ccup%28-3%2C%5Cinfty%29)
Step-by-step explanation:
<u>First inequality:</u>
<u />![n+8](https://tex.z-dn.net/?f=n%2B8%3C-2%2C%20%5C%5Cn%3C-10)
Therefore, this inequality restricts:
![n \in \mathrm{R};\: n](https://tex.z-dn.net/?f=n%20%5Cin%20%5Cmathrm%7BR%7D%3B%5C%3A%20n%3C-10)
<u>Second inequality:</u>
![< 8+n-3](https://tex.z-dn.net/?f=%3C%208%2Bn%3C5%2C%20%5C%5Cn%3E-3)
Therefore, this inequality restricts:
![n \in \mathrm{R};\: n>-3](https://tex.z-dn.net/?f=n%20%5Cin%20%5Cmathrm%7BR%7D%3B%5C%3A%20n%3E-3)
Therefore, with both of these restrictions together, we have:
.
Answer:
(a)They were treated like slaves.