Answer: 2,243.4
Step-by-step explanation:
Answer: 
Step-by-step explanation:
We know that the standard quadratic equation is ax^2+bx+c=0
Let's compare all the given equation to it and , find discriminant.
1. a=2, b= -7, c=-9
So it has 2 real number solutions.
2. a=1, b=-4, c=4

So it has only 1 real number solution.
3. a=4, b=-3, c=-1

So it has 2 real number solutions.
4. a=1, b=-2, c=-8
So it has 2 real number solutions.
5. a=3, b=5, c=3

Thus it does not has real solutions.
Answer:
64
Step-by-step explanation:
plz mark brainliest
Answer:
27 4th root (x^3)
Step-by-step explanation:
(81x) ^ 3/4
We know (ab) ^c = a^c b^c
81 ^ (3/4) * x^3/4
We can rewrite 81 as 3^4
(3^4)^(3/4) * x^3/4
We know that a^b^c = a^ (b*c)
3^(4*3/4) * x^3/4
3^(3) * x^3/4
27 * x^3/4
27 4th root (x^3)
By rearranging it:
-3x-2x-22xy+4y
=-5x-22xy+4y answer