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Romashka-Z-Leto [24]
4 years ago
5

Consider the graph of the quadratic function y = 2x2 - 4x

Mathematics
1 answer:
adell [148]4 years ago
6 0

Answer:2

Step-by-step explanation:

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Emily decided to take up Weightlifting she thought it would be
melisa1 [442]

Answer:

Common Ratio = 2

Step-by-step explanation:

Emily started with 12 lb at start.

She will double each day

So,

2nd day she will take up weight = 12 * 2 = 24

3rd day she will take up weight = 24 * 2 = 48

and so on

This is a geometric sequence, which is a sequence where each term is found by multiplying the previous term by a constant which is known as the common ratio.

Here, we are multiplying by "2" to get the next term, so we an say the common ratio is "2".

<u>Answer: Common Ratio = 2</u>

8 0
3 years ago
An automotive repair center charges $45 for any part of the first hour of labor, and $25 for any part of each additional hour. W
IceJOKER [234]
The total cost is given by the equation:
C(t) = 45 + 25(h-1) where h is the number of hours worked.

We can check for each option in turn:

Option A:

Inequality 5 < x ≤ 6 means the hour is between 5 hours (not inclusive) to 6 hours (inclusive)
Let's take the number of hours = 5
C(5) = 45 + (5-1)×25 = 145
Let's take the number of hours = 6
Then substitute into C(6) = 45 + (6-1)×25 = 170
We can't take 145 because the value '5' was not inclusive.


Option B:
The inequality is 6 < x ≤ 7
We take number of hours = 6
C(6) = 25(6-1) + 45 = 170
We take number of hours = 7
Then C(7) = 25(7-1) + 45 = 195

Option C:
The inequality is 5 < x ≤ 6
Take the number of hours = 5
C(5) = 25(5-1) + 45 = 145
Take the number of hours = 6
C(6) = 25(6-1) + 45 = 170
We can't take the value 145 as '5' was not inclusive in the range, but we can take 170

Option D:
6 < x ≤ 7
25(6-1) + 45 < C(t) ≤ 25(7-1) + 45
170 < C(t) ≤ 195

Correct answer: C


7 0
3 years ago
What’s the correct answer
Dafna11 [192]
2 number is ryt ans
6 0
3 years ago
Read 2 more answers
Find the area of the region enclosed by f(x) and the x axis for the given function over the specified u reevaluate f(x)=x^2+3x+4
lord [1]

Answer:

A = 68 unit^2

Step-by-step explanation:

Given:-

The piece-wise function f(x) is defined over an interval as follows:

                       f(x) =  { x^2+3x+4    , x < 3

                       f(x) =  { x^2+3x+4     , x≥3

                        Domain : [ -3 , 4 ]

Find:-

Find the area of the region enclosed by f(x) and the x axis

Solution:-

- The best way to tackle problems relating to piece-wise functions is to solve for each part individually and then combine the results.

- The first portion of function is valid over the interval [ -3 , 3 ]:      

                       f(x) = x^2+3x+4

- The area "A1" bounded by f(x) is given as:

                      A1 = \int\limits^a_b {f(x)} \, dx

Where,  The interval of the function { -3 , 3 ] = [ a , b ]:

                     A1 = \int\limits^a_b {x^2+3x+4} \, dx\\\\A1 = \frac{x^3}{3} + \frac{3x^2}{2} + 4x |\limits_-_3^3 \\\\A1 = \frac{3^3}{3} + \frac{3*3^2}{2} + 4*3 - \frac{-3^3}{3} - \frac{3(-3)^2}{2} - 4(-3)\\\\A1 = 9 + 13.5 +12 + 9-13.5+12\\\\A1 =42 unit^2

- Similarly for the other portion of piece-wise function covering the interval [3 , 4] :

                     f(x) = 4x+10

- The area "A2" bounded by f(x) is given as:

                      A2 = \int\limits^a_b {f(x)} \, dx

Where,  The interval of the function { 3 , 4 ] = [ a , b ]:

                     A2 = \int\limits^a_b {4x+10} \, dx\\\\A2 = 2x^2 + 10x |\limits_3^4 \\\\A2 = 2*(4)^2 + 10*4 - 2*(3)^2 - 10*3\\\\A2 = 32 + 40 - 18-30\\\\A2 =26 unit^2

- The total area "A" bounded by the piece-wise function over the entire domain [ -3 , 4 ] is given:

                     A = A1 + A2

                     A = 42 + 26

                     A = 68 unit^2

8 0
3 years ago
Can someone please help me​
seropon [69]

Answer:

131.88cm

Step-by-step explanation:

Implement the formula for circumference of a circle:

2×pi(3.14)×r, r= 21cm and pi is given as 3.14. Substitute your given values into the formula above:

2 × 3.14 × 21= 131.88cm to the nearest hundreth

7 0
3 years ago
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