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frosja888 [35]
3 years ago
11

Anyone know the answer to this algebra problem?

Mathematics
1 answer:
m_a_m_a [10]3 years ago
6 0

here you go, the answer

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The speeds of cars on a given i street we are normally distributed with a mean of 72 miles per hour and a standard deviation of
Ostrovityanka [42]

Answer: 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.

Step-by-step explanation:

Let X be a random variable that represents the speed of the drivers.

Given: population mean : M = 72 miles ,

Standard deviation: s= 3.2 miles

The probability that the drivers are traveling between 70 and 80 miles per hour based on this distribution:

P(70\leq X\leq 80)=P(\frac{70-72}{3.2}\leq \frac{X-M}{s}\leq\frac{80-72}{3.2})\\\\= P(-0.625\leq Z\leq 2.5)\ \ \ \ \ [Z=\frac{X-M}{s}]\\\\=P(Z\leq2.5)-P(Z\leq -0.625)\\\\\\ =0.9938-0.2660\ \ \ [\text{Using p-value calculator}]\\\\=0.7278

Hence, 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.

3 0
3 years ago
The shown bellow question answer
Serhud [2]

Answer:

The area of the shape can be divided into the area of the rectangle, and the area of the semi-circle.

The area of the rectangle can be found by 11*4=44

The area of a semi-circle can be found with the formula \frac{1}{2} \pi r^2 where r is the radius.

Since we know the diameter of the semi-circle is 4,

the radius will be 4 ÷ 2 = 2.

Therefore, the area of the semi-circle is \frac{1}{2}\pi 2^2=\frac{1}{2}\pi*4=2\pi

Therefore, the area of the shape is 44+2\pi or 50.283cm^2 (3 decimal places)

3 0
2 years ago
Which ordered pairs make both inequalities true? Check all that apply.
Thepotemich [5.8K]
All others did not satisfy the inequality simultaneously except #4 and #6
For #4:
2 < 5(1) + 2 i.e. 2 < 7 (true)
2 >= 1/2(1) + 1 i.e. 2 >= 3/2  (true)
For #6
2 < 5(2) + 2 i.e. 2 < 12 (true)
2 >= 1/2(2) + 1 i.e. 2 >= 2

7 0
3 years ago
Read 2 more answers
What’s the value of 5%
Firdavs [7]

Answer:

0.05 in decimal form

Step-by-step explanation:

I don't know if you accidentally left something out but if you did I can edit my answer or put the answer in the comments.

4 0
2 years ago
The sequence of transformations that can be performed on quadrilateral ABCD to show that it is congruent to quadrilateral GHIj i
Andreas93 [3]

Answer:

1).

A. Reflection across the y axis.

2).

A. Clockwise rotation about point B and a translation 20 units down.

3 0
3 years ago
Read 2 more answers
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