What is the solution to the inequality lx-4l< 3? –7 < x < –1 1 < x < 7 x < –7 or x < –1 x > 1 or x <

Question

4 years ago

11

7

2 answers:

larisa [96] · Answer 1 · 2022-01-13T22:25:44+03:00

8 0

Answer: B

Step-by-step explanation: Just took test.

lidiya [134] · Answer 2 · 2022-01-13T20:39:12+03:00

$1$

So, Option B is correct.

Step-by-step explanation:

We need to solve the inequality: $|x-4|< 3$

Solving:

$|x-4|< 3$

The absolute rule says that if |u|<a and a>0, then -a<u<a

So, applying absolute rule:

$|x-4|< 3\\-3$

We can write it as:

$x-4>-3\,\,and\,\,x-4-3+4\,\,and\,\,x1\,\,and\,\,x$

Combining the intervals:

$1$

So, Option B is correct.

Keywords: Solving inequalities

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