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3 years ago

To the nearest millimeter,a cell phone is 132 mm and 69 mm wide. What is the ratio of the width to the length

Mathematics

1 answer:

ZanzabumX [31]3 years ago

7 0

Answer:

23:44 or 1:1.91

Step-by-step explanation:

w:l =69:132 Divide each number by 3

= 23:44 Divide each number by 23

≈ 1:1.91

The width-to-length ratio is 23:44 or approximately 1:1.91

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Answer:

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Step-by-step explanation:

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2 years ago

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Wewaii [24]

Answer:

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Step-by-step explanation:

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2 years ago

Solve the following equation for n 18n^2-50=0

Firdavs [7]

$18n^2-50=0\ \ \ |+50\\\\18n^2=50\ \ \ |:18\\\\n^2=\dfrac{50}{18}\\\\n^2=\dfrac{50:2}{18:2}\\\\n^2=\dfrac{25}{9}\to n=\pm\sqrt{\dfrac{25}{9}}\\\\n=\pm\dfrac{\sqrt{25}}{\sqrt{9}}\\\\\boxed{n=-\dfrac{5}{3}\ \vee\ n=\dfrac{5}{3}}$

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3 0

2 years ago

Weights were recorded for all nurses at a particular hospital, the mean weight for an individual nurse was 135 lbs. with a stand

Aloiza [94]

Given:
population mean, μ =135
population standard deviation, σ = 15
sample size, n = 19

Assume a large population, say > 100,
we can reasonably assume a normal distribution, and a relatively small sample.
The use of the generally simpler formula is justified.

Estimate of sample mean
$\bar{x}=\mu=135$

Estimate of sample standard deviation
$\s=\sqrt{\frac{\sigma^2}{n}}$
$=\sqrt{\frac{15^2}{19}}=3.44124$ to 5 decimal places.

Thus, using the normal probability table,
$P(125$
$=P(\frac{125-135}{3.44124}$
$=P(-2.90593$
$=P(Z$
$=P(Z$

Therefore
The probability that the mean weight is between 125 and 130 lbs
P(125<X<130)=0.0731166-0.0018308
=0.0712858

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2 years ago

:)))) solve the following by factorizing: x^2-2x=120

stepladder [879]

Answer:

Step-by-step explanation:

$x^2 - 2x = 120\\x^2 - 2x - 120 = 0$