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3 years ago

PLEASE ANSWER ASAP (10 Pts)

Mathematics

2 answers:

Tatiana [17]3 years ago

7 0

X + 3.2 = - 3.5
-3.2 -3.2

x = - 6 . 7

GarryVolchara [31]3 years ago

3 0

The answer to this question is -6.7

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1. If a bicycle wheel has a diameter of 15 in. How far will the wheel rotate in 10 rotations?

WARRIOR [948]

Answer:

150 pi inches or 471.239 inches traveled

Step-by-step explanation:

First, close your eyes, and think about the distance a bike travels after one rotation of the wheel.

You will come to the realization that a full rotation of the wheel makes you travel the circumference of the wheel

The formula for circumference is 2(pi)(r) or (pi)(diameter)

We are given diameter, so let's find distance traveled for one rotation

pi(15 inches) = 15pi inches per rotation.

There are 10 rotations, so:

(15pi inches/rotation)(10 rotations) = 150pi inches travelled

150 x pi = 471.239 inches traveled

4 0

3 years ago

which one of the following proportions is true for the segments shown in the figure if lines a B and C are parallel to each othe

ycow [4]

I believe it is A because line segment AC is equal to line segment BD, and AE and BF are also the same

5 0

3 years ago

5 points

lara31 [8.8K]

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3 0

2 years ago

Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F

Svet_ta [14]

Answer:

$A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36$

Step-by-step explanation:

The equations are:

$y = x^{2} + 2x + 3$

$y = 2x + 12$

The two graphs intersect when:

$x^{2} + 2x + 3 = 2x + 12$

$x^{2} = 0$

$x_{1} = 3\\x_{2} = -3$

To find the area under the curve for the first equation:

$A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

To find the area under the curve for the second equation:

$A_{2} = \int\limits^3__-3}{2x + 12} \, dx$

To find the total area:

$A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

Simplifying the equation:

$A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx$

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).

3 0

2 years ago

Find the value of sin H rounded to the nearest hundredth, if necessary.<br> Help please

Travka [436]

Answer:

sinH ≈ 0.47

Step-by-step explanation:

sinH = $\frac{opposite}{hypotenuse}$ = $\frac{IJ}{HJ}$ = $\frac{16}{34}$ ≈ 0.47 ( to the nearest hundredth )

7 0

2 years ago