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san4es73 [151]
4 years ago
12

Evaluate 1+(-2/3)-(-m)where m = 9/2

Mathematics
1 answer:
slava [35]4 years ago
8 0

Answer:

29/6

Step-by-step explanation:

The expression that we have to evaluate in this problem is

1+(-\frac{2}{3}) -(-m)

for m=\frac{9}{2}.

First of all, we re-arrange the expression. We know that:

- The product of a positive number (+) and a negative number (-) is negative (-)

- The product of a negative number (-) and a negative number (-) is positive (+)

So we can rewrite the expression as

1-\frac{2}{3}+m

Also, we can combine the two numerical terms:

1-\frac{2}{3}=\frac{3}{3}-\frac{2}{3}=\frac{1}{3}

Therefore the expression becomes

\frac{1}{3}+m

Now we can substitute m=\frac{9}{2}, and we find:

\frac{1}{3}+\frac{9}{2}=\\\frac{2}{6}+\frac{27}{6}=\\\frac{2+27}{6}=\frac{29}{6}

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The ratio 9:7 gives you following statement:

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Then the probability that Carl will lose is

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Step-by-step explanation:

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Simplify:

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