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RideAnS [48]
2 years ago
12

Find the area of the circle. Round your answer to the nearest tenth. 9mm PLEASE HELP QUICK!!

Mathematics
1 answer:
Brilliant_brown [7]2 years ago
5 0

FOLLOW ME FOR CLEARING YOUR NEXT DOUBT

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Write the equation graphed below
kozerog [31]

Answer:

y=|x-5|-1

Step-by-step explanation:

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3 years ago
Sharif likes exersicing.He goes hill-climbing every 12 days anf goes swimming every 8 days.If je goes hill-climbing and swimming
topjm [15]
This is a lowest common multiple question.
to find the lowest common multiple, you need to find the prime factors of the two numbers:
8 = 2 , 2 , 2
12 = 2 , 2 , 3
Take out duplicates:
2,2,2,3
and multiply them together:
2*2*2*3 = 24
and that is your answer.
Easy peasy.
5 0
3 years ago
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The perimeter of a square is 176 centimeters. If the square is dilated by a scale factor of 0.25, what is the length of each sid
vovikov84 [41]

Answer:

It will be 11 for each side of the square

Step-by-step explanation:

Hope this Helped

6 0
3 years ago
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I bought a new hat for $32. What would be 5% sales tax?
vodka [1.7K]

Answer:

$1.60 for tax, $33.60 all together

Step-by-step explanation:

32 x .05 = 1.6

4 0
3 years ago
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What is the completely factored form of f(x)=x^3+4x^2+7x+6?
Reptile [31]

we are given

f(x)=x^3+4x^2+7x+6

We will use rational root theorem to find factors

We can see that

Leading coefficient =1

constant term is 6

so, we will find all possible factors of 6

6=\pm 1,\pm 2,\pm 3,\pm 6

now, we will check each terms

At x=-2:

We can use synthetic division

we get

f(-2)=0

so, x+2 will be factor

and we can write our expression from synthetic division as

f(x)=x^3+4x^2+7x+6=(x+2)(x^2+2x+3)

f(x)=(x+2)(x^2+2x+3)

now, we can find factor of remaining terms

x^2+2x+3=0

we can use quadratic formula

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

we can compare our equation with quadratic equation

we get

a=1,b=2,c=3

now, we can plug these values

x=\frac{-2+\sqrt{2^2-4\cdot \:1\cdot \:3}}{2\cdot \:1}

x=-1+\sqrt{2}i

x=\frac{-2-\sqrt{2^2-4\cdot \:1\cdot \:3}}{2\cdot \:1}

x=-1-\sqrt{2}i

so, we get

x=-1+\sqrt{2}i,\:x=-1-\sqrt{2}i

so, we can write factor as

x^2+2x+3=(x-(-1+\sqrt{2}i))(x-(-1-\sqrt{2}i))

so, we get completely factored form as

f(x)=(x+2)(x-(-1+\sqrt{2}i))(x-(-1-\sqrt{2}i))...............Answer


7 0
3 years ago
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