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Alexus [3.1K]
3 years ago
8

Let f(x)=2x-1 and g(x)=x^2 -3. Find (f o g)(-3)

Mathematics
1 answer:
anzhelika [568]3 years ago
6 0
(f o g)(-3) = (f(g(-3))
Because g is on the inside, we carry out g first.

g(x) = x^2 - 3
Substitute -3 in for x.
g(-3) = (-3)^2 - 3 = 9 - 3 = 6
g(-3) = 6

Next, carry out f on the result of g(-3)
f(6) = 2(6) - 1
      = 12 - 1
      = 11
So the answer is 11.

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Elis [28]
Chicken biscuits and syrup
6 0
3 years ago
Independent random samples of vehicles traveling past a given point on an interstate highway have been observed on monday versus
quester [9]
Hi! 

To compare this two sets of data, you need to use a t-student test:

You have the following data:

-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph

-Wednesday n2=20;  </span>x̄2=56,3 mph; s2=4,4 mph

You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

t= \frac{X1-X2}{ \sqrt{ \frac{(n1-1)* s1^{2}+(n2-1)* s2^{2} }{n1+n2-2}} * \sqrt{ \frac{1}{n1}+ \frac{1}{n2}} } =2,2510

To calculate the degrees of freedom you need to use the following equation:

df= \frac{ (\frac{ s1^{2}}{n1} + \frac{ s2^{2}}{n2})^{2}}{ \frac{(s1^{2}/n1)^{2}}{n1-1}+ \frac{(s2^{2}/n2)^{2}}{n2-1}}=33,89≈34

The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10

So, as the calculated value is higher than the critical tabulated one, we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.



5 0
3 years ago
A copy machine repairman makes $12.50 per hour plus $4 for every service call he performs. Last week he worked 34 hours and made
Anon25 [30]

z=total pay
x=hours
y=service calls

7 0
3 years ago
Francis earns $3.50 an hour mowing lawns. He also gets a $10.00 a week allowance. Bella earns $5.25 an hour babysitting and spen
Alika [10]
3.5h+10=5.25h-11
21=1.75h
12=h

3.5(12)+10=5.25(12)-11
52=52
8 0
3 years ago
Coach Pettaway is buying basketball equipment for his team. He gets a
soldier1979 [14.2K]
First, let’s all acknowledge that whoever comes up with problems like this WANTS kids to hate math...smh

I’m sure there is a prettier way to solve this, but here’s what I did:

8(2.25) + 3(22.50) =
18 + 67.50 = 85.50 per “set” of balls/jerseys
400/85.50 = 4.678 = number of “sets” he can buy. Round down to 4 so we have room for tax.

85.5 x 4 “sets”= $342
Tax on 342 is 0.06 x 342 = 20.52

$342 + 20.52 = $362.52 spent

Basketballs = 4 sets x 8 balls per set= 32
Jerseys = 4 sets x 3 jerseys per set= 12

32 basketballs, 12 jerseys, $362.52 spent

3 0
3 years ago
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