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crimeas [40]
3 years ago
9

The students in Mr. Nolan's class are writing expressions for the perimeter of a rectangle of side length  l and width w. After

they share their answers, the following expressions are on the board:
Sam:2(l+w)
Joanna:l+w+l+w
Kiyo:21+w
Erica:2w+21
Mathematics
1 answer:
Alina [70]3 years ago
6 0
Everyone has the correct answer except Kiyo.
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I have hard prolems on subtract 4.000 -6.000
anyanavicka [17]
6.000 - 4.000 = 2.000

It is a very simple equation. The easiest way to remember it would be to look at the first two numbers. 6 subtract 4 equals 2. So when you see this equation, simply for starters do 6 subtract 4, which equals 2, and then add a decimal place and the 3 zeros at the end. Does that make sense? Please let me know whether this was useful to you or not, and if you have any further questions please feel free to ask so on comments. Thank you!
8 0
3 years ago
Evaluate: 16<br> A.256<br> B.32<br> C.8<br> D.4
Hitman42 [59]

Answer:

16 ^2 = 256  

16 x 2 = 32  

16 / 2 = 8  

16 / 4 = 4

4 0
3 years ago
34. The diagram shows a sector of a circle of radius 10 cm.
Sergio [31]

Answer:

rc  length  =  10 * 8pi/5

 =   16pi

This is the circumference of the base

(a)   2pir     =   16pi  where  r  =  radius of base

  2r     =    16

   r     =  8 cm

(b)   10^2    =   h^2   +  8^2

 h^2    =   100  -  64

  =    36

h      =    6 cm

8 0
3 years ago
Read 2 more answers
6( 5-8x) +12= -54
UkoKoshka [18]
<span>6( 5-8x) +12= -54 
30-48x+12=-54 this comes from distributing(multiplying) 6x5 and 6 times -8x
30+12-48x=-54 you have to add the coefficients 30+12
42-48x=-54  
-42        -42 
-----------------------
-48x=-96 divide by -48
x=2</span>
5 0
3 years ago
Read 2 more answers
Find the two smallest possible solutions to part 1a​
bixtya [17]
<h3>Answer: A. 5/12, 25/12</h3>

============================

Work Shown:

12*sin(2pi/5*x)+10 = 16

12*sin(2pi/5*x) = 16-10

12*sin(2pi/5*x) = 6

sin(2pi/5*x) = 6/12

sin(2pi/5*x) = 0.5

2pi/5*x = arcsin(0.5)

2pi/5*x = pi/6+2pi*n or 2pi/5*x = 5pi/6+2pi*n

2/5*x = 1/6+2*n or 2/5*x = 5/6+2*n

x = (5/2)*(1/6+2*n) or x = (5/2)*(5/6+2*n)

x = 5/12+5n or x = 25/12+5n

these equations form the set of all solutions. The n is any integer.

--------

The two smallest positive solutions occur when n = 0, so,

x = 5/12+5n or x = 25/12+5n

x = 5/12+5*0 or x = 25/12+5*0

x = 5/12 or x = 25/12

--------

Plugging either x value into the expression 12*sin(2pi/5*x)+10 should yield 16, which would confirm the two answers.

7 0
3 years ago
Read 2 more answers
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