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2 years ago

write an expression that uses partial products to multiply 8 x 64. Can your expression be written another way? Explain

1 answer:

8 0

we are asked to write an expression that uses partial products to multiply 8 and 64. In this case, we can break 8 into 2 x4 and 64 into 8x8. In this case, multiplying these factors equal to 512. Any factors will do actually since it will yield the same product.

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The first part of a trip driving at 40 mph was 15 miles longer and took 30 minutes longer than the second part of the trip drivi

kenny6666 [7]

Answer:

65 miles

Step-by-step explanation:

There are two simultaneous equations . Remeber that v=d/t, 1hour = 60 minutes.

1. 40 = (d+15)/(t+0.5)

2. 50 = d/t

solving: d= 25 miles and t=0.5 hours.

The distance traveled is:

D=d+d+15

D=65 miles

5 0

2 years ago

Read 2 more answers

Complete the table of values

Agata [3.3K]

Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, $3^{-2} =
\frac{1}{3^{2} }$ .
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, $(\frac{3}{4}) ^{3} = \frac{ 3^{3} }{4^{3} }$ .
3) The zero exponent rule says that any number raised to zero is 1. For example, $3^{0} = 1$ .


Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is $y = 4^{-x}$ . The x-values are:
1) x = 0
Plug this into $y = 4^{-x}$ to find letter a:
$y = 4^{-x}\\
y = 4^{-0}\\
y = 4^{0}\\
y = 1$

2) x = 2
Plug this into $y = 4^{-x}$ to find letter b:
$y = 4^{-x}\\ 
y = 4^{-2}\\ 
y = \frac{1}{4^{2}} \\ 
y= \frac{1}{16}$

3) x = 4
Plug this into $y = 4^{-x}$ to find letter c:
$y = 4^{-x}\\ 
y = 4^{-4}\\ 
y = \frac{1}{4^{4}} \\ 
y= \frac{1}{256}$


Problem 2
The x-values are in the left column. The title of the right column tells you that the function is $y = (\frac{2}{3})^x$ . The x-values are:
1) x = 0
Plug this into $y = (\frac{2}{3})^x$ to find letter d:
$y = (\frac{2}{3})^x\\
y = (\frac{2}{3})^0\\
y = 1$

2) x = 2
Plug this into $y = (\frac{2}{3})^x$ to find letter e:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\
y = \frac{4}{9}$

3) x = 4
Plug this into $y = (\frac{2}{3})^x$ to find letter f:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}$

-------

Answers:
a = 1
b = $\frac{1}{16}$ 
c = $\frac{1}{256}$
d = 1
e = $\frac{4}{9}$
f = $\frac{16}{81}$

5 0

3 years ago

A restaurant has square dining tables.they will place table settings on each table so that there is a distance of 2 feet from ea

lakkis [162]

9 OK there you go
if you don't think this is correct then ask someone else

5 0

3 years ago

Read 2 more answers

Mrs. Stevens is wanting to buy new border for her math bulletin board in the hallway l. The length of the board is 6.9 meters. T

kiruha [24]

Answer:

The quantity of board which Mr. Stevens need to buy is 22.4 meters

Step-by-step explanation:

Given as :

The length of board = 6.9 meters

The width of board = 4.3 meters

Let The measure of new board = x meter

Now,

The measure of new board = The perimeter of board

∵ The board is of rectangle figure

As, The perimeter of rectangular board = 2 × Length + 2 × width

So, The measure of new board = 2 × Length + 2 × width

or, x = 2 × 6.9 + 2 × 4.3

or, x = 13.8 + 8.6

or, x = 22.4 meters

So, The measure of new board = x = 22.4 meters

Hence The quantity of board which Mr. Stevens need to buy is 22.4 meters Answer

3 0

2 years ago

Use quadratic regression to find

vovangra [49]

Answer:

y = 6x² -13x -5

Step-by-step explanation:

(1,-12) (2,-7) (5,80)

y = ax² + bx + c

-12 = a*1² + b*1 + c = a+b+c (1)

-7 = 4a + 2b + c (2)

80 = 25a + 5b + c (3)

(2)-(1): 3a + b = 5 (4)

(3)-(2): 21a + 3b = 87 (5)

(4)*3: 9a + 3b = 15 (6)

(5)-(6): 12a = 72 a = 6

(4) b = -13

(2) c = -5

4 0

2 years ago