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4 years ago

[(2x)^x (2x)^2x]^1/xhow do you simplify this?

Mathematics

1 answer:

Monica [59]4 years ago

5 0

Note that [ (2x)^x ]^(1/x) = 2x, and that [ (2x)^(2x) ]^(1/x) = (2x)^2 = 4x^2

Multiplying these 2 results together, we get (2x)(4x^2) = 8x^3 (answer)

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ANYONE KNOW THIS???????

anyanavicka [17]

Answer:

cant read

Step-by-step explanation:

6 0

3 years ago

The longer base of an isosceles trapezoid joins points (-3, -2) and (7, -2). One endpoint of the shorter base is (-1, 4). What a

Alex

Answer:

(5,4)

Step-by-step explanation:

We have that the longer base of an isosceles trapezoid joins points (-3, -2) and (7, -2), and one endpoint of the shorter base is (-1, 4).

The best way to find the coordinates of the other endpoint is to draw or sketch the figure on a coordinate grid.

From the graph in the attachment the coordinates of the other endpoints is (5,4).

4 0

3 years ago

19.

vichka [17]

Answer:

168

Step-by-step explanation:

Sum the parts of the ratio, 6 + 7 = 13 parts

Divide the total number of students by 13 to find the value of one part of the ratio.

364 ÷ 13 = 28 ← value of 1 part of the ratio, thus

number of girls = 6 × 28 = 168

3 0

3 years ago

Consider the probability that no less than 95 out of 152 registered voters will vote in the presidential election. Assume the pr

nikdorinn [45]

Answer:

0.3821 = 38.21% probability that no less than 95 out of 152 registered voters will vote in the presidential election.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .