2.00+1.50= 3.50.
3.50x8= 28.00
I'm assuming they each paid 41.00 dollars for two games,
41.00x8= 328.00
328.00+28.00= $356.00
Hope this is correct and/or it helps!
Sorry, didn't realize my mistake.
Step-by-step explanation:
S = { 1, 2, 3, 4, 5, 6 7, 8 }
n ( S ) = 8
Let A be the event of getting 4,
A = { 4 }
n ( A ) = 1
P ( A )
= n ( A ) / n ( S )
= 1 / 8
Therefore, the probability of spinning a 4 is 1 / 8.
S = { A, B, A, C, A, B }
n ( S ) = 6
Let Y be the event of getting C,
Y = { C }
n ( Y ) = 1
P ( Y )
= n ( Y ) / n ( S )
= 1 / 6
Therefore, the probability of spinning a C is 1 / 6.
You have to use the distance formula. sqrt((x2-x1)^2+(y2-y1)^2) So sqrt((4+3)^2+(-5-2)^2). sqrt(49+49). Sqrt(98). 9.89
SO heres what you have to do:
Hourly Spent: 60 x 4 = 240
0.10 x 240= 24
24+240=264
$264 is your answer!
Hope this helped!!! ;)
